[英]Scraping image with bs4 python
这是链接“https://www.blocket.se/annons/stockholm/samsung_note10__i_nyskick_med_kvitto/92119857”
我想提取手机的图像
"<div style="left:0%;background-image:url(https://i.blocketcdn.se/pictures/2835058804.jpg?type=original);width:100%;height:100%;background-size:contain;background-position:50% 50%;background-repeat:no-repeat;position:absolute"></div>"
当我使用 find_all 搜索时,我得到的是背景图片而不是我想要的图片(电话),或者没有
任何知道如何仅提取手机图像的人
您可以从<meta ...>
标签中提取图片网址:
import requests
from bs4 import BeautifulSoup
url = 'https://www.blocket.se/annons/stockholm/samsung_note10__i_nyskick_med_kvitto/92119857'
soup = BeautifulSoup(requests.get(url).content, 'lxml')
img_url = soup.select_one('[property="og:image"]')['content']
img_url_original = img_url.split('?')[0] + '?type=original'
print(img_url_original)
印刷:
https://i.blocketcdn.se/pictures/2835058804.jpg?type=original
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