根据键而不是值从数组中删除对象？

Question

我有一个对象数组，我想根据键在其中删除一个对象？ 我尝试使用过滤器，在 lodash 中省略，但没有任何效果。 描述可以在任何位置

输入

input = [{product: "abc", value: "123"},{name: "def", value: "234"},{description: ["abd123"]}]

预期产出

output = [{product: "abc", value: "123"},{name: "def", value: "234"}]

const result = input.filter(el => el.key !== description)

Answer 1

你可以这样声明数组：

const input = [{product: "abc", value: "123"},{name: "def", value:"234"},{description: ["abd123"]}];

并使用某些功能删除您的对象

let output = input.filter(object => !object.hasOwnProperty("description"));

以便

output = [{product: "abc", value: "123"},{name: "def", value:"234"}];

 const input = [{product: "abc", value: "123"},{name: "def", value:"234"},{description: ["abd123"]}]; let output = input.filter(object => !object.hasOwnProperty("description")); output = [{product: "abc", value: "123"},{name: "def", value:"234"}]; console.log(output);

Answer 2

如果您想删除任何具有密钥的对象，请使用 hasOwnProperty 进行检查

let input = [{product: "abc", value: "123"},{name: "def", value: "234",description:0},{description: ["abd123"]}]


let output = input.filter(el=> !el.hasOwnProperty('description'))

Answer 3

你可以这样做：

input.filter(el=> !el.description)