根據鍵而不是值從數組中刪除對象？

Question

我有一個對象數組，我想根據鍵在其中刪除一個對象？ 我嘗試使用過濾器，在 lodash 中省略，但沒有任何效果。 描述可以在任何位置

輸入

input = [{product: "abc", value: "123"},{name: "def", value: "234"},{description: ["abd123"]}]

預期產出

output = [{product: "abc", value: "123"},{name: "def", value: "234"}]

const result = input.filter(el => el.key !== description)

Answer 1

你可以這樣聲明數組：

const input = [{product: "abc", value: "123"},{name: "def", value:"234"},{description: ["abd123"]}];

並使用某些功能刪除您的對象

let output = input.filter(object => !object.hasOwnProperty("description"));

以便

output = [{product: "abc", value: "123"},{name: "def", value:"234"}];

 const input = [{product: "abc", value: "123"},{name: "def", value:"234"},{description: ["abd123"]}]; let output = input.filter(object => !object.hasOwnProperty("description")); output = [{product: "abc", value: "123"},{name: "def", value:"234"}]; console.log(output);

Answer 2

如果您想刪除任何具有密鑰的對象，請使用 hasOwnProperty 進行檢查

let input = [{product: "abc", value: "123"},{name: "def", value: "234",description:0},{description: ["abd123"]}]


let output = input.filter(el=> !el.hasOwnProperty('description'))

Answer 3

你可以這樣做：

input.filter(el=> !el.description)