如何检查字符串是否包含列表并在python中显示

Question

我有列表： lst [a,b,c,d,e]

然后输入： food

我想要输出： there is 1 d

另一个输入示例： aachen

所以输出是： there is 2 a there is 1 e

大写或小写都没有关系。

Answer 1

您可以使用collections.Counter()来计算每个字母的出现次数，然后遍历您的lst并输出每个数字出现的次数。

import collections

lst = ['a','b','c','d','e']

word = 'food'

word_count = collections.Counter(word)

for letter in lst:
    count = word_count.get(letter)
    if count:
        print(f"There is {count} {letter}")

Answer 2

Python原生方式：

l = ['a','b','c','d','e']
m = {}
s = input("Enter input string:")
for f in l:
  for k in range(len(s)):
    if f == s[k]:
      if f in m:
        m[f] = m[f] + 1 
      else:
        m[f] = 1

for j in m.keys():
  print(s,"has")
  print(m[j],j)