比较两个列表中的值，然后计算哪个列表更大

Question

绝对的初学者在这里，第一个问题张贴在这个论坛上

我有两个列表，A 和 B。我需要将它们的值一一比较，看看哪个更大。

list_A = [10, 11, 13, 30, 22, 11, 10, 33, 22, 22]
list_B = [23, 66, 12, 43, 12, 10, 44, 23, 12, 17]

在第一对 (10/23) 中，列表 B 更大。 然后我想为名为 B_bigger 的变量计算 +1，反之亦然，如果 A 列表中的值更大，则为 A 计算 +1。

结果应该是：

A_bigger = 6

B_bigger = 4

非常感谢

Answer 1

我们可以尝试使用zip以及对两个输入列表的列表理解来生成大于/小于的布尔列表。 然后，对每个列表求和以生成您想要查看的计数：

A_bigger = sum([i > j for i, j in zip(list_A, list_B)])
B_bigger = len(list_A) - A_bigger
print("A_bigger = " + str(A_bigger))
print("B_bigger = " + str(B_bigger))

这打印：

A_bigger = 6
B_bigger = 4

数据：

list_A = [10, 11, 13, 30, 22, 11, 10, 33, 22, 22]
list_B = [23, 66, 12, 43, 12, 10, 44, 23, 12, 17]

Answer 2

为此，您需要压缩这些列表。 例如：

A_bigger = 0
B_bigger = 0

for a, b in zip(list_A, list_B):
    if a > b:
        A_bigger += 1
    if b > a:
        B_bigger += 1

Answer 3

尝试这个：

a_big = 0
b_big = 0
for x,y in zip(list_A,list_B):
  if x > y:
    a_big += 1
  if y > x:
    b_big += 1

print("A_Bigger:",a_big)
print("B_Bigger:",b_big)

Answer 4

每个人都已经给出了一个很好的zip版本，所以这里是一个使用numpy 。

import numpy as np

list_A = [10, 11, 13, 30, 22, 11, 10, 33, 22, 22]
list_B = [23, 66, 12, 43, 12, 10, 44, 23, 12, 17]

a = np.array(list_A)
b = np.array(list_B)

# Find a difference between the two lists
diff = a - b

# Compare to see how many result in a positive/negative difference
# anything >0 will be because A is greater, anything <0 is because B is greater
# anything ==0 is because the values are the same 
a_greater = sum(diff > 0)  # 6
b_greater = sum(diff < 0)  # 4