我必须在python中一个一个打开多个站点

Question

我正在尝试为多个页面为亚马逊构建一个刮刀。 我已经创建了这个代码。 我也附上了输出。 我必须遍历所有这些，但是当我尝试打开链接时，它只会打开最后一个。

import pandas as pd
import ssl
import urllib3
urllib3.disable_warnings(urllib3.exceptions.InsecureRequestWarning)
ctx = ssl.create_default_context()
ctx.check_hostname = False
ctx.verify_mode = ssl.CERT_NONE     
extracted_data = []
#read the excel file
df = pd.read_excel(r'C:\Users\adelinpa\Desktop\Adelina_2\apluscontent_yes_no.xlsx')
print(df)
#convert asin column to a list
        
asin = df['asin'].tolist()
print(asin)
        
#take user input to establish MP:
marketplace = str(input('Insert MP :'))
link = []
        
        
        
if marketplace == "IT":
    for i in asin:
        length = len(asin)
        i = 0
        while i < length:
            link = "www.amazon.it/dp/" +asin[i] + '/'
            i+=1
            print(link)
        
elif marketplace == "ES":
    for i in asin:
        length = len(asin)
        i = 0
        while i < length:
            link = "www.amazon.es/dp/" + asin[i] + '/'
            i+=1
            print(link)
        
elif marketplace == "MX":
    for i in asin:
        length = len(asin)
        i = 0
        while i < length:
            link = "www.amazon.com.mx/" + asin[i] + '/'
            i += 1
            print(link)
        
elif marketplace =="BR":
    for i in asin:
        length = len(asin)
        i = 0
        while i < length:
            link = "www.amazon.com.br/dp/" + asin[i] + '/'
            i += 1
            print(link)           

输出：

www.amazon.es/dp/B07N1JPGPD/
www.amazon.es/dp/B0758LBVDC/
www.amazon.es/dp/B07MJ7GCKJ/
www.amazon.es/dp/B07N1JX25F/
www.amazon.es/dp/B07B91VB7B/
www.amazon.es/dp/B07MSKJ35L/
www.amazon.es/dp/B07M798C5Z/
www.amazon.es/dp/B07N1J7TVC/
www.amazon.es/dp/B07FR1CSWR/
www.amazon.es/dp/B07MC132XS/
www.amazon.es/dp/B07FSHLZ9H/
www.amazon.es/dp/B07M7985YJ/
www.amazon.es/dp/B07NLVRH41/
www.amazon.es/dp/B07MSKL5G5/
www.amazon.es/dp/B07B94NH1S/

Answer 1

如果我理解正确，列表link应该包含所有链接吗？

到目前为止，您没有将链接添加到列表中，而是在每次迭代中用字符串值覆盖您的列表变量。 您需要使用append而不是覆盖您的变量。

您还通过在彼此内部有两个循环来多次迭代asin （第二个循环与第一个循环相同，但对每个项目再次执行一次）。 如果使用如下所示的 for 循环，则可以减少它。

import pandas as pd
import ssl
import urllib3
urllib3.disable_warnings(urllib3.exceptions.InsecureRequestWarning)
ctx = ssl.create_default_context()
ctx.check_hostname = False
ctx.verify_mode = ssl.CERT_NONE     
extracted_data = []
#read the excel file
df = pd.read_excel(r'C:\Users\adelinpa\Desktop\Adelina_2\apluscontent_yes_no.xlsx')
print(df)
#convert asin column to a list

asin = df['asin'].tolist()
print(asin)

#take user input to establish MP:
marketplace = str(input('Insert MP :'))
link = []
 

if marketplace == "IT":
    for element in asin:
        link.append("www.amazon.it/dp/" + element + '/')

elif marketplace == "ES":
    for element in asin:
        link.append("www.amazon.es/dp/" + element + '/')

elif marketplace == "MX":
    for element in asin:
        link.append("www.amazon.com.mx/dp/" + element + '/')

elif marketplace =="BR":
    for element in asin:
        link.append("www.amazon.com.br/dp/" + element + '/')

一个更干净（而且更短）的版本可能是：

...
#take user input to establish MP:
marketplace = str(input('Insert MP :')).lower()

# extend marketplace adress if necessary
if marketplace in ['mx', 'br']:
  marketplace = 'com.' + marketplace

links = []
for element in asin:
   links.append("www.amazon." + marketplace  + "/dp/" + element + '/')

Answer 2

谢谢大家回答我的问题！ 在亚马逊网站和 asin 之间进行这种连接之后，我在打开我刚刚创建的链接时得到了 stucl。