检查文本是否只是十进制数字？

Question

有没有最有效的方法来验证 JavaScript 中的十进制数？

例如像下面这样：

01. IsDec('-7.7')      => true
02. IsDec('-18')    => true
03. IsDec('0')       => true
04. IsDec('.845')    => true
05. IsDec('0.957')     => true
06. IsDec('0x45f')  => false
07. IsDec('15,87')   => false
08. IsDec('#text') => false
09. IsDec('75.95.69')   => false
10. IsDec('')        => false
11. IsDec('someText')    => false

Answer 1

试试这样：

 console.log(isDec("-12.5")); console.log(isDec("12.5")); console.log(isDec("0")); console.log(isDec(".45")); console.log(isDec("1,5")); console.log(isDec("#ssdr")); function isDec(txt) { return !isNaN(parseFloat(txt)) && isFinite(txt); }

Answer 2

这是一个用于检查的正则表达式。

/^-?\d*\.?\d*(?<!^\.?)$/

 console.log('--- true cases ---'); console.log(isDec('-7.7')); console.log(isDec('-18')); console.log(isDec('0')); console.log(isDec('.845')); console.log(isDec('0.957')); console.log(isDec('16.')); console.log('--- false cases ---'); console.log(isDec('0x45f')); console.log(isDec('15,87')); console.log(isDec('#text')); console.log(isDec('75.95.69')); console.log(isDec('')); console.log(isDec('someText')); console.log(isDec('.')); function isDec(txt) { const regex = /^-?\\d*\\.?\\d*(?<!^\\.?)$/; return regex.test(txt); }

在这里检查结果

Answer 3

请尝试以下功能来检查十进制数

function isDecimal(n) {
   return !isNaN(parseFloat(n)) && isFinite(n);
}

答：

isDecimal('-7.7')      => true