Is there most effective way to validate decimal numbers in JavaScript?
For example like below:
01. IsDec('-7.7') => true
02. IsDec('-18') => true
03. IsDec('0') => true
04. IsDec('.845') => true
05. IsDec('0.957') => true
06. IsDec('0x45f') => false
07. IsDec('15,87') => false
08. IsDec('#text') => false
09. IsDec('75.95.69') => false
10. IsDec('') => false
11. IsDec('someText') => false
try like this:
console.log(isDec("-12.5")); console.log(isDec("12.5")); console.log(isDec("0")); console.log(isDec(".45")); console.log(isDec("1,5")); console.log(isDec("#ssdr")); function isDec(txt) { return !isNaN(parseFloat(txt)) && isFinite(txt); }
Here's a regex for checking.
/^-?\d*\.?\d*(?<!^\.?)$/
console.log('--- true cases ---'); console.log(isDec('-7.7')); console.log(isDec('-18')); console.log(isDec('0')); console.log(isDec('.845')); console.log(isDec('0.957')); console.log(isDec('16.')); console.log('--- false cases ---'); console.log(isDec('0x45f')); console.log(isDec('15,87')); console.log(isDec('#text')); console.log(isDec('75.95.69')); console.log(isDec('')); console.log(isDec('someText')); console.log(isDec('.')); function isDec(txt) { const regex = /^-?\\d*\\.?\\d*(?<!^\\.?)$/; return regex.test(txt); }
Check the result here
Please try the below function for checking decimal number
function isDecimal(n) {
return !isNaN(parseFloat(n)) && isFinite(n);
}
ans :
isDecimal('-7.7') => true
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