如何打印用户从该列表中输入名称的完整列表？ PYTHON

Question

我已经能够找到大量有关从列表中选择值的信息，但我想从其中包含的值中选择一个列表。 问题是我不希望它像做一堆 ' if那样冗长，因为那是矫枉过正。

有没有办法使用该值打印整个列表？ 这是为了帮助我以后的计算课程。 我应该从前几年就知道这一点，但由于我课程的性质，我的同龄人可能不知道。

这是相关代码：

Doggo_Database = [['Lilly', 'Jack Russell', 'White', 'F', 2009, 'Medium'],
                  ['Winston', 'Pug', 'Brown', 'M', 2010, 'Small'],
                  ['Bo', 'Doberman', 'Brown', 'M', 2011, 'Large'],
                  ['Shep', 'Border Collie', 'Black', 'M', 2006, 'Large'],
                  ['Rodney', 'Jack Russell', 'Grey', 'F', 2010, 'Medium'],
                  ['Butch', 'Bulldog', 'White', 'F', 2011, 'Medium'],
                  ['Sally', 'Boston Terrier', 'Brown', 'F', 2013, 'Small']]
names = [Doggo_Database[0][0], Doggo_Database[1][0], Doggo_Database[2][0], Doggo_Database[3][0], Doggo_Database[4][0], Doggo_Database[5][0], Doggo_Database[6][0]]
name_select = input('Do you know the name of the Doggo? If yes, state the name. If no, state NO in capital letters. ')
while name_select != 'NO' and name_select not in names:
    print('This is not a valid entry.')
    name_select = input('Please try again: ')
    
if name_select != 'NO':
    for name in names:
        if name_select == name:
            print(name_select)
            Data_name = 
elif name_select == 'NO':
    print("We're currenly unable to find the doggo until more search options are availble")
else:
    print('a logic error has occurred')

我为此使用基础 python，而不是 SQL

Answer 1

我Data_name =您正在寻找Data_name =相应列表 鉴于您的代码编写方式，您可以这样做：

Data_name = [i for i in Doggo_Database if i[0]==name_select][0]

例如如果name_select = 'Bo'

结果将是

['Bo', 'Doberman', 'Brown', 'M', 2011, 'Large']

Answer 2

如果您可以使用 python dict （作为狗 DB），它将使您的代码更清晰。

db = {'Lilly': ['Jack Russell', 'White', 'F', 2009, 'Medium'],
      'Winston': ['Pug', 'Brown', 'M', 2010, 'Small']}

name_select = input('Do you know the name of the Doggo? If yes, state the name. If no, state NO in capital letters. ')
while name_select != 'NO' and name_select not in db:
    print('This is not a valid entry.')
    name_select = input('Please try again: ')

if name_select != 'NO':
    print(f'Dog details: {db.get(name_select)}')
else:
    print("We're currenly unable to find the doggo until more search options are availble")