删除撇号后的字符串内容

Question

我正在尝试从句子中删除撇号标点符号'之后的字符串内容。

例如，给出一句话This is the world's first engine. You'll learn more about this later. This is the world's first engine. You'll learn more about this later.

预期的输出是This is the world first engine. You learn more about this later. This is the world first engine. You learn more about this later.

我可以使用re.sub()删除撇号 ' 。 但是，我无法删除撇号后的内容

re.sub(r'[^\\w]', ' ', value)

我也使用过 python replace() 。 但是，这不是通用的解决方案

value.replace("'s", "")

任何帮助表示赞赏。 谢谢你！

Answer 1

要删除str中的撇号和尾随字母，您可以使用以下代码。

import re

s = "This is the world's first engine. You'll learn more about this later."
s = re.sub(r'\'\w+', '', s)
print(s)

输出： This is the world first engine. You learn more about this later. This is the world first engine. You learn more about this later.

模式\\'\\w+匹配后跟一个或多个单词字符的撇号， re.sub()用于用空字符串 ( '' ) 替换此模式的任何匹配项。

Answer 2

您可以使用re.sub()如下

import re
def clean(value):
    return re.sub(r'\'\w{,2}', '', value)

print(clean("This is the world's first engine. You'll learn more about this later"))

Answer 3

试试这个（我想正则表达式有更简单的解决方案）：

s="This is the world's first engine. You'll learn more about this later."

s=' '.join(list(map(lambda x: x[:x.find("'")] if "'" in x else x, s.split(' '))))

>>> print(s)
'This is the world first engine. You learn more about this later.'