[英]How to fetch name of all files in google drive using google drive api?
我正在尝试获取 google 驱动器中所有文件的名称,但问题是我只能获取特定数量的文件,如何删除此限制并获取所有文件,这是 google 在其网站上提供的代码
我正在使用谷歌驱动器 API v3
from __future__ import print_function
import pickle
import os.path
from googleapiclient.discovery import build
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request
# If modifying these scopes, delete the file token.pickle.
SCOPES = ['https://www.googleapis.com/auth/drive.metadata.readonly']
def main():
"""Shows basic usage of the Drive v3 API.
Prints the names and ids of the first 10 files the user has access to.
"""
creds = None
# The file token.pickle stores the user's access and refresh tokens, and is
# created automatically when the authorization flow completes for the first
# time.
if os.path.exists('token.pickle'):
with open('token.pickle', 'rb') as token:
creds = pickle.load(token)
# If there are no (valid) credentials available, let the user log in.
if not creds or not creds.valid:
if creds and creds.expired and creds.refresh_token:
creds.refresh(Request())
else:
flow = InstalledAppFlow.from_client_secrets_file(
'credentials.json', SCOPES)
creds = flow.run_local_server(port=0)
# Save the credentials for the next run
with open('token.pickle', 'wb') as token:
pickle.dump(creds, token)
service = build('drive', 'v3', credentials=creds)
# Call the Drive v3 API
results = service.files().list(
pageSize=10, fields="nextPageToken, files(id, name)").execute()
items = results.get('files', [])
if not items:
print('No files found.')
else:
print('Files:')
for item in items:
print(u'{0} ({1})'.format(item['name'], item['id']))
if __name__ == '__main__':
main()
在这段代码中有一个变量 pageSize ,它的值是 10,如果我增加它的值,这样我就可以获取更多文件,但我想获取所有文件,所以我该怎么做。
Files.list有一个名为 pagesize 的可选参数
pageSize integer 每页返回的最大文件数。 即使在到达文件列表末尾之前,部分或空的结果页面也是可能的。 可接受的值为 1 到 1000,包括 1 到 1000。 (默认值:100)
您已将您的 pageSize=10 设置为 1000,然后使用 nextPageToken 选择下一组行(如果有更多行)。
我不是 python 开发人员,以下代码是猜测。
page_token = saved_start_page_token;
while page_token is not None:
response = service.changes().list(pageToken=page_token,
pageSize=1000, fields="nextPageToken, files(id, name)").execute()
page_token = response.get('nextPageToken')
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