[英]How to decode lines encoded as base64 from file?
我需要解码文件中的行。
到目前为止,这是我的代码:
def decode(self) -> list:
"""
Decode file with key.
For correct answer you have to convert file lines from base64 to utf-8.
To decode one line you have to take a UNICODE value of a letter, subtract cipher step and take mod of 255.
After that you have to convert that number back to a character.
Example: key = 'test', decoded_data = "+%'"
'+' -> (43 - 448) % 255 -> 'i' -> ... -> 'ice'
:return: List of decoded lines
"""
decoded_lines1 = []
decoded_lines = []
lines = self.read_code_from_file()
for line in lines:
decoded_lines.append(base64.b64decode(line).decode())
for decoded_line in decoded_lines:
for letter in decoded_line:
decoded_lines1.append(chr((ord(letter) - sum([ord(i) for i in self.key])) % 255))
return decoded_lines1
解码行:
[')-.7)-\x06\x06AOO', '-57)-0\x06\x06JASJAOOASJ', ')07)2\x06\x06AJSAJAJOAJJAAO',...]
我的 output 由于某种原因所有的字母都是单独的,下面 output 的一小部分在解码我的 output 后等于 decoded_lines 的第一个列表元素:
['-', '1', '2', ';', '-', '1', '\n', '\n', 'E', 'S', 'S', ...]
预计 output:
['-12;-1\n\nESS', ...]
有什么办法可以用逗号分隔行而不是用逗号分隔每个字母? 非硬编码密钥等于 1016。
问题是你 append 每个字符,一个一个地解码到decoded_lines1
当你做
.append(chr((ord(letter) - sum([ord(i) for i in self.key])) % 255))
相反,您想对decoded_line
中的每个字符执行此操作,从所有解码字符中创建一个字符串,然后将该字符串append 到decoded_lines1
。
for decoded_line in decoded_lines:
new_line = []
for letter in decoded_line:
new_line.append(chr((ord(letter) - sum([ord(i) for i in self.key])) % 255))
decoded_lines1.append("".join(new_line))
但是您可以通过组合for line in lines
和for decoded_line in decoded_lines
循环来进一步简化代码:
def decode(self):
decoded_lines = []
lines = self.read_code_from_file()
for line in lines:
decoded_line = base64.b64decode(line).decode()
new_line = []
for letter in decoded_line:
new_line.append(chr((ord(letter) - sum([ord(i) for i in self.key])) % 255))
decoded_lines.append("".join(new_line))
return decoded_lines
问题出在下面的代码中:
for decoded_line in decoded_lines:
for letter in decoded_line:
decoded_lines1.append(chr((ord(letter) - sum([ord(i) for i in self.key])) % 255))
在这里,您在将 append 解码行添加到列表中时逐个字母地附加到列表中。
所以,我将解码后的字母存储到一个字符串中,然后将 append 存储到列表中。
for decoded_line in decoded_lines:
temp=""
for letter in decoded_line:
temp=temp+chr((ord(letter) - sum([ord(i) for i in self.key])) % 255)
decoded_lines1.append(temp)
最终代码将如下所示:
def decode(self) -> list:
"""
Decode file with key.
For correct answer you have to convert file lines from base64 to utf-8.
To decode one line you have to take a UNICODE value of a letter, subtract cipher step and take mod of 255.
After that you have to convert that number back to a character.
Example: key = 'test', decoded_data = "+%'"
'+' -> (43 - 448) % 255 -> 'i' -> ... -> 'ice'
:return: List of decoded lines
"""
decoded_lines1 = []
decoded_lines = []
lines = self.read_code_from_file()
for line in lines:
decoded_lines.append(base64.b64decode(line).decode())
for decoded_line in decoded_lines:
temp=""
for letter in decoded_line:
temp=temp+chr((ord(letter) - sum([ord(i) for i in self.key])) % 255)
decoded_lines1.append(temp)
return decoded_lines1
你一行中只有一个词吗? 它是一个句子吗? 它由多个单词组成,那么你的第二个循环应该在单词上,然后第三个循环应该在字母上。 代码应该是这样的
def decode(self) -> list:
"""
Decode file with key.
For correct answer you have to convert file lines from base64 to utf-8.
To decode one line you have to take a UNICODE value of a letter, subtract cipher step and take mod of 255.
After that you have to convert that number back to a character.
Example: key = 'test', decoded_data = "+%'"
'+' -> (43 - 448) % 255 -> 'i' -> ... -> 'ice'
:return: List of decoded lines
"""
decoded_lines1 = []
decoded_lines = []
lines = self.read_code_from_file()
for line in lines:
decoded_lines.append(base64.b64decode(line).decode())
for decoded_line in decoded_lines:
for word in decoded_line.split():
docoded_word=''
for letter in word:
docoded_word+=(chr((ord(letter) - sum([ord(i) for i in self.key])) % 255))
decoded_lines1.append(docoded_word)
return (decoded_lines1)
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