[英]What's wrong with this method...?
import java.util.Scanner;
public class InputCalculator {
public static void inputThenPrintSumAndAverage(){
Scanner scanner = new Scanner(System.in);
boolean first = true;
int sum = 0;
int count = 0;
int avg = 0;
while(true){
int number = scanner.nextInt();
boolean isAnInt = scanner.hasNextInt();
if(isAnInt){
sum += number;
count++;
avg = Math.round((sum)/count);
}else{
System.out.println("SUM = " + sum + " AVG = " + avg);
break;
}
scanner.nextLine();
}
scanner.close();
}
}
当输入为“1,2,3,4,5,a”时,我认为它没有读取输入 5,结果 sum = 10 和 avg = 2! 为什么会发生? 顺便说一句,它只是一个方法而不是整个代码!
当scanner.nextInt() 为您提供'5' 时,下一行'scanner.hasNextInt() 为false。 只需更改行顺序
import java.util.Scanner;
public class InputCalculator {
public static void inputThenPrintSumAndAverage(){
Scanner scanner = new Scanner(System.in);
boolean first = true;
int sum = 0;
int count = 0;
int avg = 0;
while(true){
boolean isAnInt = scanner.hasNextInt();
if(isAnInt){
int number = scanner.nextInt();
sum += number;
count++;
avg = Math.round((sum)/count);
}else{
System.out.println("SUM = " + sum + " AVG = " + avg);
break;
}
scanner.nextLine();
}
scanner.close();
}
}
你也可以像清理代码一样
import java.util.Scanner;
public class InputCalculator {
public static void inputThenPrintSumAndAverage(){
Scanner scanner = new Scanner(System.in);
int sum = 0;
int count = 0;
while( scanner.hasNextInt() ){
int number = scanner.nextInt();
sum += number;
count++;
}
scanner.close();
double avg = Math.round((sum)/count);
System.out.println("SUM = " + sum + " AVG = " + avg);
}
}
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