如何在字典中显示多个项目？

Question

我有一个程序有一个搜索选项，如果 chicken 或 Chicken 在库存中，它会通过键入 chi（不区分大小写）来提取项目。 问题是如何让 function 返回所有包含 chi 的项目？

例如，如果我的库存中有 Chickens、chicken、chickens 和 Chicken，我应该可以输入 chi，它应该会打印出关于每个项目的所有信息。

受影响的代码（不是完整的程序）：

def search(self, query):
    #SEARCHING DATA BASED ON CLOSEST CHARACTER MATCH - NOT CASE SENSITIVE
    for id in self.items:
        if str(query) == id or self.items[id]['name'].lower().startswith(str(query).lower()):
            return id, self.items[id]['name'], self.items[id]['qty']
    return None

我该如何解决？

完整的测试程序代码：

import os
import json

class Inventory:
    def __init__(self):
        #AT LAUNCH GROUPS AND LOADING FUNCTION
        self.items = {}
        self.load()

    def remove(self, ID):
        #REMOVING ITEMS FOR LISTS AND OUTPUT DOCUMENT
        del self.items[str(ID)]
        self.save()

    def add(self, ID, name, qty):
        #ADDING ITEMS FOR LISTS AND OUTPUT DOCUMENT
        self.items[str(ID)] = {"name": name, "qty": qty}
        self.save()

    def update(self, ID, update):
        #UPDATING ITEMS FOR LISTS AND OUTPUT DOCUMENT
        self.items[str(ID)]["qty"] += update
        self.save()

    def search(self, query):
        #SEARCHING DATA BASED ON CLOSEST CHARACTER MATCH - NOT CASE SENSITIVE
        output = []
        for id in self.items:
            if str(query) == id or self.items[id]['name'].lower().startswith(str(query).lower()):
                output.append((id, self.items[id]['name'], self.items[id]['qty']))
        if output: return output
        else: return None

    def __str__(self):
        #FORMATTING
        out = ""
        for id, d in self.items.items():
            out += f"ID Number : {id} \nItem Name : {d['name']}\nQuantity : {d['qty']}\n"
            out += "----------\n"
        return out
    
    def save(self):
        #WHERE TO SAVE TO
        with open('data.txt','w') as outfile:
           json.dump(self.items, outfile)

    def load(self):
        #WHERE TO PUT DATA FROM WHEN RELAUNCHING PROGRAM
        try:
            with open('data.txt','r') as json_file:
               self.items = json.load(json_file)
        except:
            print("Can't load old inventory, starting fresh")
            self.items = {}


def menuDisplay():
    #MENU FOR PROGRAM 
    """Display the menu"""
    print('=============================')
    print('= Inventory Management Menu =')
    print('=============================')
    print('(1) Add New Item to Inventory')
    print('(2) Remove Item from Inventory')
    print('(3) Update Inventory')
    print('(4) Search Item in Inventory')
    print('(5) Print Inventory Report')
    print('(99) Quit')


def add_one_item(inventory):
    #ADDING PROMPT AND ERROR CHECKING
    print('Adding Inventory')
    print('================')
    while True:
        try:
            new_ID = int(input("Enter an ID number for the item: "))
            if inventory.search(new_ID):
                print("ID number is taken, please enter a different ID number")
                continue
            new_name = input('Enter the name of the item: ')
            new_qty = int(input("Enter the quantity of the item: "))
            inventory.add(new_ID, new_name, new_qty)
            break
        except Exception as e:
            print("Invalid choice! try again! " + str(e))
            print()


def remove_one_item(inventory):
    #REMOVING PROMPT AND ERROR CHECKING
    print('Removing Inventory')
    print('==================')
    while True:
        try:
            removing = int(input("Enter the item's ID number to remove from inventory: "))
            if inventory.search(removing):
                inventory.remove(removing)
            else:
                print("Item not in inventory")
                continue
            break
        except Exception as e:
            print("Invalid choice! try again! " + str(e))
            print()


def ask_exit_or_continue():
    #OPTION TO CONTINUE OR QUITE PROGRAM
    return int(input('Enter 98 to continue or 99 to exit: '))


def update_inventory(inventory):
    #UPDATING PROMPT AND ERROR CHECKING
    print('Updating Inventory')
    print('==================')
    while True:
        try:
            ID = int(input("Enter the item's ID number to update: "))
            if inventory.search(ID):
                update = int(input("Enter the updated quantity. Enter 5 for additional or -5 for less: "))
                inventory.update(ID, update)
            else:
                print("ID number is not in the system, please enter a different ID number")
                continue
            break
        except Exception as e:
            print("Invalid choice! try again! " + str(e))
            print()

def search_inventory(inventory):
    #SEARCHING PROMPT AND ERROR CHECKING
    print('Searching Inventory')
    print('===================')
    while True:
        try:
            search = input("Enter the name of the item: ")
            result = inventory.search(search)
            if result is None:
                print("Item not in inventory")
                continue
            else:
                for found in result:
                    ID, name, qty = found
                    print('ID Number: ', ID)
                    print('Item:     ', name)
                    print('Quantity: ', qty)
                    print('----------')
            break
        except Exception as e:
            print("Invalid choice! try again! " + str(e))
            print()


def print_inventory(inventory):
    #PRINT CURRENT LIST OF ITEMS IN INVENTORY
    print('Current Inventory')
    print('=================')
    print(inventory)


def main():
    #PROGRAM RUNNING COMMAND AND ERROR CHECKING
    inventory = Inventory()
    while True:
        try:
            menuDisplay()
            CHOICE = int(input("Enter choice: "))
            if CHOICE in [1, 2, 3, 4, 5]:
                if CHOICE == 1:
                    add_one_item(inventory)
                elif CHOICE == 2:
                    remove_one_item(inventory)
                elif CHOICE == 3:
                    update_inventory(inventory)
                elif CHOICE == 4:
                    search_inventory(inventory)
                elif CHOICE == 5:
                    print_inventory(inventory)
                exit_choice = ask_exit_or_continue()
                if exit_choice == 99:
                    exit()
            elif CHOICE == 99:
                exit()
        except Exception as e:
            print("Invalid choice! try again!"+str(e))
            print()

        # If the user pick an invalid choice,
        # the program will come to here and
        # then loop back.


main()

Answer 1

---

def search(self, query):
        #SEARCHING DATA BASED ON CLOSEST CHARACTER MATCH - NOT CASE SENSITIVE
        output = []
        for id in self.items:
            if str(query) == id or self.items[id]['name'].lower().startswith(str(query).lower()):
                output.append((id, self.items[id]['name'], self.items[id]['qty']))
        if output:
            return output
        else: 
            return None

如果你觉得这无法解释，也许我问错了问题。 您应该尝试更好地解释更多。

Answer 2

该代码返回第一个匹配项。 此搜索返回所有匹配项。

    def search(self, query):
    """ Search items for all matching id's in query.
    """
    output = [id for id in self.items if str(query).upper() in id.upper()]
    return output if output != [] else None

作为一个独立的演示，我构建了一个 Class，它有一个包含 3 个项目的数据库和一个搜索方法。

对于搜索方法，我在列表理解中使用“if str(query).upper() in id.upper()”。

class Db:
    def __init__(self):
        self.items = {
            'Picture1': {'name': 'name1', 'qty': 1},
            'Picture2': {'name': 'name2', 'qty': 2},
            'Picture3': {'name': 'name3', 'qty': 3}}
    def search(self, query):
        return [(id, self.items[id]['name'], self.items[id]['qty'])
        for id in self.items if str(query).upper() in id.upper()]

db = Db()
db.search('pic')
db.search('ure2')