如何使用矩在数组中获得最近的下一次？

Question

我想找到最接近给定时间的下一次，我从堆栈溢出中得到了这段代码，但我无法得到想要的结果

 // Current time in millis const now = +moment('10:07', 'HH:mm').format('x'); // List of times const times = ["10:00", "10:18", "23:30", "12:00"]; // Times in milliseconds const timesInMillis = times.map(t => +moment(t, "HH:mm").format("x")); function closestTime(arr, time) { return arr.reduce(function(prev, curr) { return Math.abs(curr - time) < Math.abs(prev - time)? curr: prev; }); } const closest = moment(closestTime(timesInMillis, now)).format('HH:mm'); // closest is 10:00 but i want the next time 10:18 console.log(closest);

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Answer 1

完全不需要片刻

24小时时间可排序，可直接比较

 const times = ["10:00", "10:18", "23:30", "12:00"].sort(); const getClosest = targetTime => times.find(time => time >= targetTime) || "N/A"; console.log(getClosest("10:07")); console.log(getClosest("11:30")); console.log(getClosest("13:30")); console.log(getClosest("23:40")); // not available in array