[英]Assign unique ID based on values in EITHER of two columns
这不是这个问题的重复。 在标记重复项之前,请完整阅读问题。
我有一个这样的data.frame:
library(tidyverse)
tibble(
color = c("blue", "blue", "red", "green", "purple"),
shape = c("triangle", "square", "circle", "hexagon", "hexagon")
)
color shape
<chr> <chr>
1 blue triangle
2 blue square
3 red circle
4 green hexagon
5 purple hexagon
我想像这样添加一个group_id
列:
color shape group_id
<chr> <chr> <dbl>
1 blue triangle 1
2 blue square 1
3 red circle 2
4 green hexagon 3
5 purple hexagon 3
困难在于我想按color
或shape
的独特值进行分组。 我怀疑解决方案可能是使用列表列,但我不知道如何。
我们可以在base R
中使用duplicated
df1$group_id <- cumsum(!Reduce(`|`, lapply(df1, duplicated)))
-输出
df1
# A tibble: 5 x 3
# color shape group_id
# <chr> <chr> <int>
#1 blue triangle 1
#2 blue square 1
#3 red circle 2
#4 green hexagon 3
#5 purple hexagon 3
或使用tidyverse
library(dplyr)
library(purrr)
df1 %>%
mutate(group_id = map(., duplicated) %>%
reduce(`|`) %>%
`!` %>%
cumsum)
df1 <- structure(list(color = c("blue", "blue", "red", "green", "purple"
), shape = c("triangle", "square", "circle", "hexagon", "hexagon"
)), row.names = c(NA, -5L), class = c("tbl_df", "tbl", "data.frame"
))
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