如何 select 仅在给定的所有日期范围内存在的那些记录

Question

我想 select 只有所有日期都存在重复数据计数的数据。

示例我的表数据是：

用户身份	row_created
8SRWS3hMR	2020-12-14 00:13:31
8SRWS3hMR	2020-12-14 00:35:06
8SRWS3hMR	2020-12-14 12:11:37
8SRWS3hMR	2020-12-14 13:16:27
8SRWS3hMR	2020-12-14 16:30:00
8SRWS3hMR	2020-12-14 19:25:11
8SRWS3hMR	2020-12-14 19:27:07
8SRWS3hMR	2020-12-15 17:14:06
8SRWS3hMR	2020-12-16 14:53:54

如果我 select 的日期范围在2020-12-14到2020-12-17之间，那么 output 应该是 Z37A6259CC0C1DAE299A7866489DFF0BD。

如果我 select 日期范围在2020-12-14到2020-12-16之间，那么 output 应该低于

用户身份	全部的	row_created
8SRWS3hMR	7	2020-12-14 00:13:31
8SRWS3hMR	1	2020-12-15 17:14:06
8SRWS3hMR	1	2020-12-16 14:53:54

我试过下面的查询

select user_id, count(user_id) as total, row_created from reward
where user_id = '8SRWS3hMR' AND DATE(row_created) BETWEEN '2020-12-14' AND '2020-12-17'
group by DATE(row_created);

但根据我的要求， output 应该是 null 因为在BETWEEN日期范围内我已经通过'2020-12-17' 。

请忽略语法错误。

Answer 1

您可以按如下方式使用HAVING子句：

SELECT USER_ID,
       COUNT(USER_ID) AS TOTAL,
       ROW_CREATED
  FROM REWARD
 WHERE USER_ID = '8SRWS3hMR'
   AND DATE(ROW_CREATED) BETWEEN '2020-12-14' AND '2020-12-17'
 GROUP BY DATE(ROW_CREATED) 
 HAVING COUNT(DISTINCT DATE(ROW_CREATED)) = datediff('2020-12-17', '2020-12-14') + 1;

- 更新

SELECT * FROM
(SELECT USER_ID,
       COUNT(USER_ID) AS TOTAL,
       ROW_CREATED,
       COUNT(DISTINCT DATE(ROW_CREATED)) OVER (PARTITION BY USER_ID) AS CNT
  FROM REWARD
 WHERE USER_ID = '8SRWS3hMR'
   AND DATE(ROW_CREATED) BETWEEN '2020-12-14' AND '2020-12-17'
 GROUP BY USER_ID, DATE(ROW_CREATED) 
) T WHERE CNT = datediff('2020-12-17', '2020-12-14') + 1

Answer 2

这有点复杂，因为您需要按日期汇总。 您可以使用 window 函数：

SELECT r.*
FROM (SELECT USER_ID, DATE(ROW_CREATED) as date, COUNT(*) AS TOTAL,
             MIN(ROW_CREATED) as ROW_CREATED,
             COUNT(*) OVER (PARTITION BY USER_ID) as num_days,
             DATEDIFF(x.end_date, x.start_date) + 1 AS total_days
      FROM REWARD R CROSS JOIN
           (SELECT DATE('2020-12-14') as START_DATE, DATE('2020-12-17') as END_DATE
           ) params
      WHERE USER_ID = '8SRWS3hMR' AND
            ROW_CREATED >= x.start_date AND
            ROW_CREATE <= x.end_date + interval 1 day
      GROUP BY DATE(ROW_CREATED) 
     ) R
WHERE num_days = total_days;

子查询按天汇总。 它包括两个方面：

• USER_ID的不同天数。
• 总天数。

为了避免多次输入相同的日期，这些日期在子查询中定义。 另请注意，日期比较已重新安排。 不使用DATE() function，而是使用不等式。 这使得表达式与索引更兼容。

Answer 3

select user_id, count(user_id) as total, row_created from reward where user_id = '8SRWS3hMR' AND DATE(row_created) >= '2020-12-14' AND DATE(row_created) <= '2020-12-17' group by DATE (row_created) 有 count(user_id) >= DATEDIFF(row_created, '2020-12-17')