Javascript 将 URL 解析为 $.getJSON 的参数

Question

我正在尝试将URL与前端中的多个其他参数一起解析为参数，以将JSON 请求发送到我的 ZEF0F93C83E374876A61DA0D4D4D16F36ABZ4 后端，但未发现已知错误

Django urls.py 路径：

path("updateAssignment/<iD>/<body>/<deadline>/<user>/<url>/<game>/<aK>/<seoTitle>/<payment>/<wordCount>/<category>/<state>/", Dashboard.update_assignment, name="updateAssignment")

Javascript $.getJSON 请求

function updateAssignment(assignmentId){

const assignmentUpdateEndpoint = "/updateAssignment/";



let body =  encodeURIComponent(document.getElementById("Assignment-Body"+assignmentId).value);
let deadline =  encodeURIComponent(document.getElementById("Assignment-Deadline"+assignmentId).value);
let user =  encodeURIComponent(document.getElementById("Assignment-User"+assignmentId).value);
let url =   encodeURIComponent(document.getElementById("Assignment-URL"+assignmentId).value);
let game =  encodeURIComponent(document.getElementById("Assignment-Game"+assignmentId).value);
let additionalKeywords =  encodeURIComponent(document.getElementById("Assignment-Additional-Keywords"+assignmentId).value);
let seoTitle =  encodeURIComponent(document.getElementById("Assignment-SEOtitle"+assignmentId).value);
let payment =  encodeURIComponent(document.getElementById("Assignment-Payment"+assignmentId).value);
let wordCount =  encodeURIComponent(document.getElementById("Assignment-WordCount"+assignmentId).value);
let category =  encodeURIComponent(document.getElementById("Assignment-Category"+assignmentId).value);
let state =  encodeURIComponent(document.getElementById("Assignment-State"+assignmentId).value);
assignmentId = encodeURIComponent(assignmentId);

let reqUrl = assignmentUpdateEndpoint +  assignmentId + "/" + body + "/" + deadline +"/" + user + "/" + url + "/" + game + "/" + additionalKeywords + "/" + seoTitle + "/"  + payment + "/" +  wordCount + "/" + category + "/" + state + "/";

$.getJSON(reqUrl).done((response) => {
    
});

该请求仅在真正的 URL 被解析时引发错误，因此问题必须与它相关以及我猜它是如何编码的。 帮助会很棒。

Answer 1

通过使用 $.ajax 而不是 $.getJSON 来修复它。

 $.ajax({ type: "get", url: endpoint, data: {}, sucess: (response) => { }});

以正确的格式将数据传输到服务器。

Javascript 将 URL 解析为 $.getJSON 的参数

问题描述

1 个解决方案

解决方案1
0 已采纳 2021-01-10 09:09:46

Javascript 将 URL 解析为 $.getJSON 的参数

问题描述

1 个解决方案

解决方案1 0 已采纳 2021-01-10 09:09:46

解决方案1
0 已采纳 2021-01-10 09:09:46