[英]Check if there is an ascending order in a list of list of integers (Python)
给出这样的列表列表:
[[2, 7], [1, 4], [0, 5, 6]]
我如何检查此列表中是否存在有效的升序。 例如,这将是 True 因为我可以形成这个订单:
[2,4,5]
我需要一种算法,它可以以某种方式为具有任意大小列表的任意大列表找到有效顺序。 没有 integer 值会重复并且子列表已排序。
编辑:这是我目前尝试过的,但它不会扩展到更大的列表。
allNumbers = [[2, 7], [1, 4], [0, 5, 6]]
smallest = min(allNumbers[0])
largest = max(allNumbers[2])
for n in allNumbers[1]:
if smallest < n < largest:
return True
您可以使用像这样的贪心算法来解决它。
a = [[2, 7], [1, 4], [0, 5, 6]]
current = min(a[0])
possible = True
for l in a[1:]:
possible = False
for i in l:
if i >= current:
possible = True
current = i
break
if not possible:
break
print(possible) #returns True
对于每个子列表,找到仍然大于前一个最小元素的最小元素。 如果没有这样的元素,那么就没有上升路径。
from math import inf
def ascend(xss):
smallest = -inf
path = []
for xs in xss:
smallest = min(x for x in xs if x > smallest)
path.append(smallest)
return path
>>> ascend([[2, 7], [1, 4], [0, 5, 6]])
[2, 4, 5]
>>> ascend([[2, 7], [1, 4], [0, 5, 6], [0]])
Traceback (most recent call last):
...
ValueError: min() arg is an empty sequence
这是我的答案。
def tell_if_the_lists_are_in_order(lists):
min_first = min(lists[0]) # for empty input, return True.
prev_min = min_first
for sublist in lists[1:]:
min_num = min(sublist)
max_num = max(sublist)
if max_num <= prev_min:
return False
prev_min = min(x for x in sublist if x > prev_min)
return True
这是我的回答:
def IsAscending(list):
ascend = True
int a;
for i in list:
if i == 0:
a = list[i]
else:
if list[i] >= a:
a = list[i]
else:
ascend = False
return ascend
这是我得出的最终解决方案
def validList(chLocations):
ascendingOrder = []
smallest = min(chLocations[0])
maximum = max(chLocations[-1])
ascendingOrder.append(smallest)
chLocations = chLocations[1:]
for i in range(len(chLocations)-1):
for number in chLocations[i]:
if number > max(ascendingOrder):
ascendingOrder.append(number)
break
ascendingOrder.append(maximum)
if sorted(ascendingOrder) == ascendingOrder:
return True
else:
return False
>>> validList([[2, 7], [1, 4], [0, 5, 6]])
True
>>> validList([[1, 3], [7], [2]])
False
解释:
[[2, 7], [1, 4], [0, 5, 6]] --> [2,4,5] == True
[[1, 3], [7], [2]] --> [1,7,2] == False
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