根据其他人的内容添加额外的列（在R中）

Question

我有一个带有 3 个 qc 的数据框。 我想创建第 4 列，其结果将取决于所有 3 个 qc。 条件：至少 2 个必须为“坏”才能在 qc4 中显示为坏，否则为好。

  ID qc1  qc2  qc3
1 AV bad  good bad
2 AX bad  bad  bad
3 AS good good good
4 AW good bad  bad

结果

  ID qc1  qc2  qc3  q4
1 AV bad  good bad  bad
2 AX bad  bad  bad  bad
3 AS good good good good
4 AW good bad  bad  bad

Answer 1

我们可以使用ifelse rowSums逻辑向量的值创建“坏”、“好”

nm1 <- grep("^qc\\d+$", names(df), value = TRUE)
df$q4 <- ifelse(rowSums(df[nm1] == "bad") >=2, "bad", "good")
df
#  ID  qc1  qc2  qc3   q4
#1 AV  bad good  bad  bad
#2 AX  bad  bad  bad  bad
#3 AS good good good good
#4 AW good  bad  bad  bad

---

或者另一种选择是使用rowwise/c_across从dplyr

library(dplyr)
df %>% 
   rowwise %>%
   mutate(q4 = c("good", "bad")[1+(sum(c_across(starts_with('qc')) ==
       'bad') >= 2)]) %>%
   ungroup

数据

df <- structure(list(ID = c("AV", "AX", "AS", "AW"), qc1 = c("bad", 
"bad", "good", "good"), qc2 = c("good", "bad", "good", "bad"), 
    qc3 = c("bad", "bad", "good", "bad")), class = "data.frame",
    row.names = c("1", 
"2", "3", "4"))

Answer 2

另一个使用rowSums基本 R 选项

df$qc4 <- c("good", "bad")[1 + (rowSums(df == "bad") >= 2)]

这样

> df
  ID  qc1  qc2  qc3  qc4
1 AV  bad good  bad  bad
2 AX  bad  bad  bad  bad
3 AS good good good good
4 AW good  bad  bad  bad

数据

> dput(df)
structure(list(ID = c("AV", "AX", "AS", "AW"), qc1 = c("bad", 
"bad", "good", "good"), qc2 = c("good", "bad", "good", "bad"),
    qc3 = c("bad", "bad", "good", "bad"), qc4 = c("bad", "bad",
    "good", "bad")), row.names = c("1", "2", "3", "4"), class = "data.frame")