Laravel eloquent 返回错误数据

Question

我有条件数据，它在返回数据时忽略了这些条件：

工作正常

$orders = Order::where('user_id', $user->id)->with(['customer', 'laundry', 'driver', 'driver.user', 'progresses' => function($p){
  $p->orderby('created_at', 'asc');
}, 'progresses.progress', 'services'])->get();

返回错误数据

$orders = Order::where('user_id', $user->id)->with(['customer', 'laundry', 'driver', 'driver.user', 'progresses' => function($p){
                $p->orderby('created_at', 'asc');
            }, 'progresses.progress', 'services'])
            ->where('id', 'like', '%'.$this->search.'%')
            ->orWhere('transport', 'like', '%'.$this->search.'%')
            ->orWhere('amount', 'like', '%'.$this->search.'%')
            ->orWhere('weight', 'like', '%'.$this->search.'%')
            ->orWhere('total', 'like', '%'.$this->search.'%')
            ->paginate(10);

问题

第二个查询返回所有orders并忽略where('user_id', '=', $user->id) 。

问题

1. 为什么它忽略where('user_id', '=', $user->id)
2. 如何解决？

Answer 1

您应该在这里对您的搜索LIKE查询进行分组

Order::with(
     [
       'customer', 
       'laundry', 
       'driver', 
       'driver.user', 
       'progresses' => function($p) {
          $p->orderby('created_at', 'asc');
       }, 
       'progresses.progress', 
       'services'
     ]
    )->where('user_id', $user->id)
    ->where(function($q) {
        $q->where('id', 'like', '%'.$this->search.'%')
        ->orWhere('transport', 'like', '%'.$this->search.'%')
        ->orWhere('amount', 'like', '%'.$this->search.'%')
        ->orWhere('weight', 'like', '%'.$this->search.'%')
        ->orWhere('total', 'like', '%'.$this->search.'%');
    })->paginate(10);

所以查询字符串看起来像：

WHERE user_id = ? 
AND 
(id LIKE ? OR transport LIKE ? OR amount LIKE ? OR weight LIKE ? OR total LIKE ?)

它将忽略where('user_id', '=', $user->id)因为orWhere在您的搜索LIKE查询