Laravel eloquent 返回錯誤數據

Question

我有條件數據，它在返回數據時忽略了這些條件：

工作正常

$orders = Order::where('user_id', $user->id)->with(['customer', 'laundry', 'driver', 'driver.user', 'progresses' => function($p){
  $p->orderby('created_at', 'asc');
}, 'progresses.progress', 'services'])->get();

返回錯誤數據

$orders = Order::where('user_id', $user->id)->with(['customer', 'laundry', 'driver', 'driver.user', 'progresses' => function($p){
                $p->orderby('created_at', 'asc');
            }, 'progresses.progress', 'services'])
            ->where('id', 'like', '%'.$this->search.'%')
            ->orWhere('transport', 'like', '%'.$this->search.'%')
            ->orWhere('amount', 'like', '%'.$this->search.'%')
            ->orWhere('weight', 'like', '%'.$this->search.'%')
            ->orWhere('total', 'like', '%'.$this->search.'%')
            ->paginate(10);

問題

第二個查詢返回所有orders並忽略where('user_id', '=', $user->id) 。

問題

1. 為什么它忽略where('user_id', '=', $user->id)
2. 如何解決？

Answer 1

您應該在這里對您的搜索LIKE查詢進行分組

Order::with(
     [
       'customer', 
       'laundry', 
       'driver', 
       'driver.user', 
       'progresses' => function($p) {
          $p->orderby('created_at', 'asc');
       }, 
       'progresses.progress', 
       'services'
     ]
    )->where('user_id', $user->id)
    ->where(function($q) {
        $q->where('id', 'like', '%'.$this->search.'%')
        ->orWhere('transport', 'like', '%'.$this->search.'%')
        ->orWhere('amount', 'like', '%'.$this->search.'%')
        ->orWhere('weight', 'like', '%'.$this->search.'%')
        ->orWhere('total', 'like', '%'.$this->search.'%');
    })->paginate(10);

所以查詢字符串看起來像：

WHERE user_id = ? 
AND 
(id LIKE ? OR transport LIKE ? OR amount LIKE ? OR weight LIKE ? OR total LIKE ?)

它將忽略where('user_id', '=', $user->id)因為orWhere在您的搜索LIKE查詢