检查 ISO 字符串日期是否在两个日期之间

Question

我想检查中间日期是否在左右日期之间，如何在 Javascript 中完成此操作，它们是ISO String 。

From 2021-01-30T05:00:00.000Z <-> Date 2021-01-31T22:18:46Z <-> To 2021-01-31T05:00:00.000Z

如何验证2021-01-31T22:18:46Z介于2021-01-30T05:00:00.000Z和2021-01-31T05:00:00.000Z

Answer 1

function getElapsedMS(strOfD1, strOfD2) {
var d1 = new Date(strOfD1);
var d2 = new Date(strOfD2);
return d1-d2;
}

var d2d1 = getElapsedMS("2021-01-31T22:18:46Z", "2021-01-30T05:00:00.000Z");
var d2d3 = getElapsedMS("2021-01-31T22:18:46Z", "2021-01-31T05:00:00.000Z");
if (d2d1 * d2d3 < 0) { // can have more consideration to avoid overflow
//d2 is between d1 and d3
}

Answer 2

Unix 时间戳

每个日期都可以表示为milliseconds since epoch数，因此我们可以将每个日期转换为毫秒，并比较一个日期是否在另一个日期之后。

例子：

const dateA = new Date("2021-01-30T05:00:00.000Z");
const dateB = new Date("2021-01-31T05:00:00.000Z");

const dateC = new Date("2021-01-31T22:18:46Z");

// We use getTime() method to get the date as milliseconds since epoch
const isDateCBetweenAandB = dateA.getTime() <= dateC.getTime() && dateC.getTime() <= dateB.getTime();

console.log(isDateCBetweenAandB);

Answer 3

两个简单的选择...

按字典顺序比较日期字符串

 const From = "2021-01-30T05:00:00.000Z" const date = "2021-01-31T22:18:46Z" const To = "2021-01-31T05:00:00.000Z" if (From.localeCompare(date) <= 0 && To.localeCompare(date) >= 0) { console.log("Date is in range") } else { console.log("Date is not in range") }

或将日期字符串解析为Date实例或时间戳并进行数字比较

 const From = new Date("2021-01-30T05:00:00.000Z") const date = new Date("2021-01-31T22:18:46Z") const To = new Date("2021-01-31T05:00:00.000Z") if (From <= date && To >= date) { console.log("Date is in range") } else { console.log("Date is not in range") }

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注意：如果您使用的是 Typescript，它不喜欢在数字上比较Date实例。 比较Date.prototype.valueOf()或Date.prototype.getTime()代替

Answer 4

你可以比较一下它的 unix 时间戳试试：

Date.parse('2021-01-31T22:18:46Z');

Answer 5

主要思想是我们只需要比较Date 。

但是，如果您使用.moment或new Date()来解析date-time UTC ，您会发现一个有趣的

moment("2021-01-31T22:18:46Z").format("YYYY-MM-DD") // "2021-02-01"
new Date("2021-01-31T22:18:46Z") // Mon Feb 01 2021 05:18:46 GMT+0700 (Indochina Time)

因此，如果compareDate像2021-01-31T05:00:00.000Z ，那么您将得到预期的结果。

 const fromDate = moment("2021-01-30T05:00:00.000Z").format("YYYY-MM-DD"); const conpareDate = moment("2021-01-31T05:00:00.000Z").format("YYYY-MM-DD"); const toDate = moment("2021-01-31T05:00:00.000Z").format("YYYY-MM-DD"); console.log({fromDate, conpareDate, toDate}); console.log(moment(conpareDate).isBetween(fromDate, toDate, undefined, '(]'));

 <script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.29.1/moment.min.js"></script>

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如果还想准确比较日期，可以通过这种方式实现（但说实话，不推荐）。

 const fromDate = '2021-01-30T05:00:00.000Z'.split('-'); const conpareDate = '2021-01-31T22:18:46Z'.split('-'); const toDate = '2021-01-31T05:00:00.000Z'.split('-'); const partStringToInt = (str) => parseInt(str, 10); const compareBetween = (a, b, c) => partStringToInt(a) <= partStringToInt(b) && partStringToInt(b) <= partStringToInt(c); const result = compareBetween(fromDate[0], conpareDate[0], toDate[0]) // Year && compareBetween(fromDate[1], conpareDate[1], toDate[1]) // Month && compareBetween(fromDate[2].substring(0, 2), conpareDate[2].substring(0, 2), toDate[2].substring(0, 2)); // Day console.log(result);