[英]Find total duration (in minutes) between multiple rows with overlaps
我有下表:
start end
('19:48:43', '21:12:43')
('21:16:36', '21:17:36')
('21:19:22', '21:46:22')
('21:22:41', '22:03:41')
('21:23:29', '22:04:29')
考虑到重叠,我需要知道start
和end
之间的总时间(以分钟为单位)。 鉴于上表,计算将如下所示:
end
- start
= 84 分钟end
- start
= 1 分钟end
和第 3 行的start
之间的差,即 45 分钟总计 = 84 + 1 + 45 = 130 分钟
我正在使用 SQLite。 到目前为止,我还没有找到任何解决方案。
使用表的 2 个副本到表本身和聚合的LEFT
连接:
WITH cte AS (
SELECT DISTINCT
COALESCE(MIN(ts.start), t.start) start,
COALESCE(MAX(te.end), t.end) end
FROM tablename t
LEFT JOIN tablename ts ON t.start BETWEEN ts.start AND ts.end
LEFT JOIN tablename te ON t.end BETWEEN te.start AND te.end
GROUP BY t.start, t.end
)
SELECT SUM(strftime('%s', end) - strftime('%s', start)) / 60 total
FROM cte
或更简单:
WITH cte AS (
SELECT DISTINCT
COALESCE(
(SELECT MIN(t2.start)
FROM tablename t2
WHERE t1.start BETWEEN t2.start AND t2.end), t1.start) start,
COALESCE(
(SELECT MAX(t2.end)
FROM tablename t2
WHERE t1.end BETWEEN t2.start AND t2.end), t1.start) end
FROM tablename t1
)
SELECT SUM(strftime('%s', end) - strftime('%s', start)) / 60 total
FROM cte
请参阅演示。
结果:
全部的 |
---|
130 |
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