在 python 的字符串列表中找到确切的单词列表？

Question

我有两个字符串列表：

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

我想检查links中有哪些grids 。 所以我为此写了一个程序：

import re

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

for search in grids:
    for text in links:
        result = re.findall('\\b' + search + '\\b', text, flags=re.IGNORECASE)
        print(result)

OUTPUT：

['north']
['north']
[]
[]
[]
[]
['northeast']
[]
[]
['south']

我几乎得到了 output 但不明白为什么我会在 output 中得到这些空白，所以我可以为这个获得更简单和干净的替代品吗？

Answer 1

可能不需要正则表达式。 只需检查字符串是否存在。

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']
for l in links:
    print(f'{l} contains {[x for x in grids if x.lower() in l.lower().split("-")]}')

Output

north-northeast contains ['north', 'noRtheast']
north-south contains ['north', 'soUth']

Answer 2

当常规 Exp 找不到任何内容时，您的代码打印结果也会出现。 if检查数组是否为空，您可以添加一些

import re

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

for search in grids:
    for text in links:
        result = re.findall('\\b' + search + '\\b', text, flags=re.IGNORECASE)
        if len(result):
            print(result)

Answer 3

我不知道图书馆“re”，但我想我可以像这样解决你的问题：

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

for search in grids:
    for text in links:
        if search.lower() in text.lower():
            print('find '+search+' in '+text+' !') 

string 上的 method.lower() 会将所有基于大小写的字符小写，如果字符串search在字符串text中，则运算符in将返回 true。

Answer 4

好吧我有误会，你可以在比较之前拆分链条：

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

for search in grids:
    for text in links:
        for text_split in text.split('-'):
            if search.lower() == text_split.lower():
                print('find '+search+' in '+text+' !')

OUTPUT：

find north in north-northeast !
find north in north-south !
find noRtheast in north-northeast !
find soUth in north-south !