[英]I would like to ask if there's a way to shorten this ternary statement?
我想知道如何在这里缩短三元语句的可能性? TIA
data_items.attributes.promo_banner.promo_join_button_style === 'primary-flat' ? 'primary-flat' : data_items.attributes.promo_banner.promo_join_button_style === 'secondary-flat' ? 'secondary-flat' : data_items.attributes.promo_banner.promo_join_button_style === 'tertiary-flat' ? 'tertiary-flat' : data_items.attributes.promo_banner.promo_join_button_style === 'primary-animated' ? 'primary-animated' : data_items.attributes.promo_banner.promo_join_button_style === 'secondary-animated' ? 'secondary-animated' : data_items.attributes.promo_banner.promo_join_button_style === 'tertiary-animated' ? 'tertiary-animated' : 'error' "
为了便于阅读,请使用较短的变量名称来存储值。 然后,由于您在输入值与 styles 之一匹配时返回输入值,因此您可以将 styles 放入一个数组中,然后您可以使用Array.includes
一次测试它们:
button_styles = ['primary-flat', 'secondary-flat', 'tertiary-flat', 'primary-animated', 'secondary-animated', 'tertiary-animated' ];
promo_button_style = data_items.attributes.promo_banner.promo_join_button_style;
button_styles.includes(promo_button_style) ? promo_button_style : 'error'
请注意,对于大型 arrays 一个Set
(带有has
)会更有效:
button_styles = new Set(['primary-flat', 'secondary-flat', ...])
button_styles.has(promo_button_style) ? promo_button_style : 'error'
你可以这样做:
const dataStyle = data_items.attributes.promo_banner.promo_join_button_style;
dataStyle === "primary-flat"
? "primary-flat"
: dataStyle === "secondary-flat"
? "secondary-flat"
: dataStyle === "tertiary-flat"
? "tertiary-flat"
: dataStyle === "primary-animated"
? "primary-animated"
: dataStyle === "secondary-animated"
? "secondary-animated"
: dataStyle === "tertiary-animated"
? "tertiary-animated"
: "error";
顺便说一句,您不应该使用如此长的三元运算符。 对于此类代码,请尝试使用 switch 语句。
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