[英]I would like to ask if there's a way to shorten this ternary statement?
我想知道如何在這里縮短三元語句的可能性? TIA
data_items.attributes.promo_banner.promo_join_button_style === 'primary-flat' ? 'primary-flat' : data_items.attributes.promo_banner.promo_join_button_style === 'secondary-flat' ? 'secondary-flat' : data_items.attributes.promo_banner.promo_join_button_style === 'tertiary-flat' ? 'tertiary-flat' : data_items.attributes.promo_banner.promo_join_button_style === 'primary-animated' ? 'primary-animated' : data_items.attributes.promo_banner.promo_join_button_style === 'secondary-animated' ? 'secondary-animated' : data_items.attributes.promo_banner.promo_join_button_style === 'tertiary-animated' ? 'tertiary-animated' : 'error' "
為了便於閱讀,請使用較短的變量名稱來存儲值。 然后,由於您在輸入值與 styles 之一匹配時返回輸入值,因此您可以將 styles 放入一個數組中,然后您可以使用Array.includes
一次測試它們:
button_styles = ['primary-flat', 'secondary-flat', 'tertiary-flat', 'primary-animated', 'secondary-animated', 'tertiary-animated' ];
promo_button_style = data_items.attributes.promo_banner.promo_join_button_style;
button_styles.includes(promo_button_style) ? promo_button_style : 'error'
請注意,對於大型 arrays 一個Set
(帶有has
)會更有效:
button_styles = new Set(['primary-flat', 'secondary-flat', ...])
button_styles.has(promo_button_style) ? promo_button_style : 'error'
你可以這樣做:
const dataStyle = data_items.attributes.promo_banner.promo_join_button_style;
dataStyle === "primary-flat"
? "primary-flat"
: dataStyle === "secondary-flat"
? "secondary-flat"
: dataStyle === "tertiary-flat"
? "tertiary-flat"
: dataStyle === "primary-animated"
? "primary-animated"
: dataStyle === "secondary-animated"
? "secondary-animated"
: dataStyle === "tertiary-animated"
? "tertiary-animated"
: "error";
順便說一句,您不應該使用如此長的三元運算符。 對於此類代碼,請嘗試使用 switch 語句。
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