[英]How do you make python use the order of the letters of a string as part of a dictionary with values for the amount of times each unique letter appears
[英]how do you make something loop a specific amount of times in python?
你好,我正在尝试制作一个战锤 40k 骰子滚轮,我制作了这个代码,但是它没有滚动正确数量的骰子
import random
count = 0
dice_to_roll=input("how many dice are you rolling? ")
hit = input("what do you hit on? ")
print("rolling dice!!!!!!")
while str(count) < dice_to_roll:
die = random.randint(1, 6)
count = count + 1
if str(die) >= hit:
print(die)
else:
print("done")
input
正在返回一个字符串。 使另一个成为字符串并检查相等性是比较字符串的长度,而不是值。 要使您的工作正常,请使用int(input(...))
并删除您正在执行的str()
强制转换。
代码:
import random
dice_to_roll = int(input("how many dice are you rolling? "))
hit = int(input("what do you hit on? "))
print ("rolling dice!!!!!!")
for i in range(dice_to_roll):
die = random.randint(1,6)
if die>=hit:
print(f"dice result:{die},hit:{hit},hit success!")
else:
print(f"dice result:{die},hit:{hit},hit failed!")
print("done")
结果:
how many dice are you rolling? 1
what do you hit on? 3
rolling dice!!!!!!
dice result:6,hit:3,hit success!
done
不要将您的count
转换为字符串,而是尝试将您的输入dice_to_roll
转换为 int。
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