使用动态 xml 结构将 xml 文件解析为 csv

Question

我一直在学习 python，目前正在解析 XML 文件并转换为 CSV 文件。 我能够迭代 XML 文件，但不需要确定如何存储列值，尤其是当 XML 值不一致时。 XML 文件位置

Output 预期： CSV 文件 output

到目前为止，我有基本的 python 代码，需要帮助我可以根据正确的 csv 列中的数据来存储和打印值：

import xml.etree.cElementTree as ET
file_path = "Candidate.xml"
tree = ET.parse('Candidate.xml')
root = tree.getroot()
print(root.tag, root.attrib)
for child in root:
    print(child.tag, child.attrib)

Answer 1

这会有点复杂但可行：

#first collect your data:
data = []
rows = root.findall('.//rows')
for row in rows:
    items = [row.attrib['id'],
            row.find('./column[@name="Organization"]'),
            row.find('./column[@name="Location"]'),
            row.find('./column[@name="Candidate.Address"]/Address1[@name="Candidate.ResidentialAddress"]'),
            row.find('./column[@name="Candidate.Address"]/Address1[@name="Candidate.OfficeAddress"]'),
            row.find('./column[@name="Candidate.GivenName"]'),
            row.find('./column[@name="Candidate.Phone"]')]
    
    #insert the data into a line
    line = []
    for item in items:        
        if item is None:
            line.append("")
        else:
            try:
                line.append(item.text.strip())
            except:
                line.append(item.strip())
    data.append(line)

#finally, prepare your csv:
headers = ["id","Organization","Location","ResidentialAddress","OfficeAddress",".GivenName","Phone"]
with open('candidates.csv', 'w', encoding='UTF8', newline='') as f:
    writer = csv.writer(f)
    writer.writerow(headers)
    writer.writerows(data)

output 应该是您正在寻找的。