以 dd.mm.yyyy 格式获取母亲节日期

Question

我试图通过 Javascript 获得母亲节日期（5 月的第一个星期日）。 但是我的代码的结果是 0.4.2021。 哪里有错，或者有更简单的方法来获取母亲节日期（dd.mm.yyyy）（德国时区）。

 var currentYear = new Date().getFullYear() var mayFirst = new Date(currentYear + '-05-01'); var dayOfWeek = mayFirst.getUTCDay(); var firstSunday; if (dayOfWeek === 0) { firstSunday = mayFirst; } else { firstSunday = new Date(); firstSunday.setDate(1 + (7 - dayOfWeek)); } var mothersDay = new Date(firstSunday); mothersDay.setDate(firstSunday.getUTCDate() + 7); mothersDay = new Date(mothersDay); console.log(mothersDay.getDay() + "." + mothersDay.getMonth() + "." + mothersDay.getFullYear());

Answer 1

这是执行此操作的正确方法，没有容易出错的计算或字符串连接，包括将其格式化为 DD.MM.YYYY：

 // Mother's Day is the second sunday in May const d = new Date(); d.setMonth(4); // May d.setDate(8); // May 8 is the earliest possible date // while not a sunday, move to next day while (d.getUTCDay()) d.setDate(d.getDate() + 1); const result = new Intl.DateTimeFormat('de-DE', { day: "2-digit", month: "2-digit", year: "numeric"}).format(d); document.body.innerHTML += result;

Answer 2

getMonth()是基于0的，所以你需要加 1。 您还想使用getDate()而不是getDay()来获取日期的日期值。

我假设您想获得 5 月的第二个星期日，因为您的代码下面的行增加了 7 天。 如果你想要第一个星期日，你也应该删除这条线。

mothersDay.setDate(firstSunday.getUTCDate() + 7);

 var currentYear = new Date().getFullYear() var mayFirst = new Date(currentYear + '-05-01'); var dayOfWeek = mayFirst.getUTCDay(); var firstSunday; if (dayOfWeek === 0) { firstSunday = mayFirst; } else { firstSunday = new Date(); firstSunday.setDate(1 + (7 - dayOfWeek)); } var mothersDay = new Date(firstSunday); mothersDay.setDate(firstSunday.getUTCDate() + 7); mothersDay = new Date(mothersDay); console.log(mothersDay.getDate() + "." + (mothersDay.getMonth() + 1) + "." + mothersDay.getFullYear());