[英]the best way to make a flatList by iterating over a single object array with different key-value pairs
通过迭代具有不同键值对的单个 object 数组来制作 flatList 的最佳方法是什么
例子:
[
{
"boteria_chat_aht": "33:55:31",
"boteria_chat_queue": 2,
"boteria_chat_tm1r": "00:00:00",
"boteria_chat_tmr": "00:00:00",
"boteria_current_chats": 2,
"boteria_finished_session_percentage": 71.43,
"boteria_sessions": 7,
"fbmessenger_chat_aht": "00:00:00",
"fbmessenger_chat_queue": 0,
"fbmessenger_chat_tm1r": "00:00:00",
"fbmessenger_chat_tmr": "00:00:00",
"fbmessenger_current_chats": 0,
"fbmessenger_finished_session_percentage": 0,
"fbmessenger_sessions": 0,
"inbound_abandoned": 0,
"inbound_aht": "00:00:00",
"inbound_asa": "00:00:00",
"inbound_handled": 0,
"inbound_queue": 0,
"inbound_received": 0,
"mercadolivreperguntas_chat_aht": "00:00:00",
"mercadolivreperguntas_chat_queue": 0,
"mercadolivreperguntas_chat_tm1r": "00:00:00",
"mercadolivreperguntas_chat_tmr": "00:00:00",
"mercadolivreperguntas_current_chats": 0,
"mercadolivreperguntas_finished_session_percentage": 0,
"mercadolivreperguntas_sessions": 0,
"mercadolivreposvenda_chat_aht": "00:00:00",
"mercadolivreposvenda_chat_queue": 0,
"mercadolivreposvenda_chat_tm1r": "00:00:00",
"mercadolivreposvenda_chat_tmr": "00:00:00",
"mercadolivreposvenda_current_chats": 0,
"mercadolivreposvenda_finished_session_percentage": 0,
"mercadolivreposvenda_sessions": 0,
"sla": 0,
"telegram_chat_aht": "00:00:00",
"telegram_chat_queue": 0,
"telegram_chat_tm1r": "00:00:00",
"telegram_chat_tmr": "00:00:00",
"telegram_current_chats": 0,
"telegram_finished_session_percentage": 0,
"telegram_sessions": 0,
"whatsapp_chat_aht": "29:27:04",
"whatsapp_chat_queue": 0,
"whatsapp_chat_tm1r": "01:02:52",
"whatsapp_chat_tmr": "01:05:59",
"whatsapp_current_chats": 0,
"whatsapp_finished_session_percentage": 100,
"whatsapp_sessions": 18
}
]
我设法做到这一点的方式是创建一个新的对象数组,接收这些值并按每种类型分隔
例子:
[
{
Whatsapp...
}
{
telegram...
}
]
如果索引等于 0,我将返回 whatsapp,否则,我将返回当前索引
但我认为这不是最好的方法。
你能帮助我吗?
那么有很多方法可以遍历数组。 您可以使用 map 方法,但成本会很高,因为它会创建一个新数组。
array.map((element) => { /* your function */ })
或者你可以使用 forEach 方法
array.forEach((element) => { /* your function */ })
如果您询问不同的键值,而不仅仅是创建一个新数组并将元素推送到新数组中。
const newarray = [];
array.forEach((element) => { newarray.push(element)})
它将所有键名的值和索引为 0 的值存储到对象数组中的最后一个值用于填充数组https://medium.com/@wisecobbler/4-ways-to-populate-an-array-在-javascript-836952aea79f
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