Python 泡菜 discord.py

Question

我想将代码集成到机器人的 discord 中。 该代码有效，但是当我制作机器人时，会出现此类错误（忽略 on_ready Traceback 中的异常（最后一次调用）：文件“C:\Python39\lib\site-packages\discord\client.py”，第 343 行，在 _run_event 等待 coro( args, kwargs) 文件“C:\Users}{\Desktop\bot\tes2.py”，第 93 行，on_ready alertList = pickle.load(infile) AttributeError: Can't get attribute 'Alert ' 在 <module ' main ' 上来自 'C:\Users\}{\Desktop\bot\tes2.py'> ）。 请告诉我如何修复它们？

from time import sleep
from threading import Thread, Lock
import os
import pickle
import discord
from discord.ext import commands
from config import settings

bot = commands.Bot(command_prefix = settings['prefix'], help_command=None)


@bot.event
async def on_ready():
    print('Logged in as')
    print(bot.user.name)
    print(bot.user.id)
    print('Bot is ready')
    print('--------------------')
    channel = bot.get_channel(825351852988170254)
    await channel.send(f'Ready')

    class Alert:
        ticker = "NA"
        price = float(0)
        way = 1

        def __init__(self, stock, p, w):
            self.ticker = stock
            self.price = p
            self.way = w

        # Stopping the alert after is has hit the target
        def stopAlert(self, alert, Alertlist):
            Alertlist.remove(alert)
            outfile = open(filename, "wb")
            pickle.dump(alertList, outfile)
            outfile.close()


        async def checkPrice(self, alertlist):
            while (True and stop):
                for alert in alertlist:
                    if (alert.way == str(1)):
                        if (float("%.2f" % ((si.get_live_price(alert.ticker))))) >= float(alert.price):
                            await channel.send('test1')
                            Alert.stopAlert(Alert, alert, alertlist)


                    elif (alert.way == str(2)):
                        if ((float("%.2f" % ((si.get_live_price(alert.ticker))))) <= float(alert.price)):
                            await channel.send('test2')
                            Alert.stopAlert(Alert, alert, alertlist)


        async def createAlert(self, alertList):
            stock = input("\n    What is the ticker symbol of the stock?\n     :: ")
            price = -1.0
            while (price < 0.0):
                try:
                    price = float(input("    What is the price you want to hit?\n     :: "))
                    if (price < 0):
                        await channel.send('Invalid price!')
                except ValueError:
                    await channel.send('Invalid input!')

            try:
                ("%.2f" % ((si.get_live_price(stock))))
                alert = Alert(stock, price, way)
                alertList.append(alert)
                outfile = open(filename, "wb")
                pickle.dump(alertList, outfile)
                outfile.close()
                await channel.send("Alert created successfully!")
            except AssertionError:
                await channel.send("      " + "-" * 21)
                await channel.send("     | Stock doesn't exist |")
                await channel.send("      " + "-" * 21)

        async def printAlert(self, alert):
            await channel.send("Ticker: {} to hit price: {}".format(alert.ticker.upper(), alert.price))


    filename = "alerts"

    try:
        infile = open(filename, "xb")
    except FileExistsError:
        infile = open(filename, "rb")

    try:
        infile = open(filename, "rb")
        alertList = pickle.load(infile)
        infile.close()
    except EOFError:
        alertList = list()

    stop = True

    t = Thread(target=Alert.checkPrice, args=(Alert, alertList,))
    t.start()


@bot.command()
async def above(ctx, *, arg):
    pass


bot.run(settings['token'])

Answer 1

该错误是因为在定义 class 时，它的名称仍然不可用。 有两种可能的解决方案：

1. 使用self.anything代替 class 名称

2. 在代码开头粘贴from __future__ import annotations 。 它应该允许你做你已经在做的事情而不会引发任何错误