[英]Double for loop in list comprehension
我对这段代码有疑问:
num = 111
num_list = list(map(int, str(num)))
i=len(num_list)
t=2**(i-1)
answer = sum([x*(l**2) for x in reversed(num_list) for l in range(len(num_list))])
if answer % 5 == 0:
print(answer, "is divisible by 5")
else:
print(answer, "is not divisible by five")
是的,如果你测试它确实有效,但它给了我:
15 is divisible by 5
代替:
7 is not divisible by 5
所以基本上我的代码所做的是它需要一个二进制数并变成十进制并测试小数是否可以被 5 整除。不要问我怎么做,但我知道我的列表理解和我的双循环有一些问题. 请帮忙,谢谢!
您将二进制转换为十进制的逻辑有点不对劲。 尝试这个:
answer = sum([x*(2**l) for l, x in enumerate(reversed(num_list))])
>>> answer
7
你也可以这样做:
num = 111
num_list = list(map(int, str(num)))
i=len(num_list)
t=2**(i-1)
answer = 0
for l in num_list:
answer += l*t
t=int(t/2)
if answer % 5 == 0:
print(answer, "is divisible by 5")
else:
print(answer, "is not divisible by five")
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