[英]Creating map of boost::tuple<std::string, std::string, int>and std::vector<int>
[英]const std::map<boost::tuples::tuple, std::string>?
// BOOST Includes
#include <boost/assign.hpp> // Boost::Assign
#include <boost/assign/list_of.hpp> // Boost::Assign::List_Of
#include <boost/assign/std/map.hpp> // Boost::Assign::Map_List_Of
#include <boost/tuple/tuple.hpp> // Boost::Tuples
// STD Includes
#include <map>
#include <vector>
#include <string>
// Using namespaces
using namespace std;
using namespace boost;
using namespace boost::assign;
// Consts
const map<string, string> query_map = map_list_of<string, string>
("4556_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 4556")
("7552_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 7552")
("234x_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 2344 OR PMU_ID = 2345 OR PMU_ID = 2346 OR PMU_ID = 2347 OR PMU_ID = 2348")
("813x_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 8132 OR PMU_ID = 8133 OR PMU_ID = 8134 OR PMU_ID = 8135 OR PMU_ID = 8136");
const map<string, std::vector<int>> vector_map = map_list_of<string, std::vector<int>>
("4556", list_of(4556))
("7552", list_of(7552))
("234x", list_of(2344)(2345)(2346)(2347)(2348))
("813x", list_of(8132)(8133)(8134)(8135)(8136));
使用boost - 可以初始化const std :: containers进行测试等。使用const std :: map或std :: map非常简单,如上面的代码所示。 创建一个const map<string, std::vector<int>>
有点复杂 - 但仍然相当容易。
我想提出一个const std::map<boost::tuples::tuple<string, string, string>, string>
但是我没有初始化它。 还有其他人有运气吗?
// Typedefs
typedef boost::tuples::tuple<string, string, string> x3_string_tuple;
// Constants
const map<x3_string_tuple, string> query_selector_map = map_list_of<x3_string_tuple, string>
("4556", "SELECT", "FILENAME"), "4556_SELECT_FILENAME"); // ETC.
我尝试了这个,它失败了,因为地图的键需要具有可比性(使用std::less
,因此需要有一个operator<
defined)。 boost::tuple
的比较运算符在头文件boost/tuple/tuple_comparison.hpp
中定义。
包含它,这段代码工作正常:
#include <boost/assign/list_of.hpp>
#include <boost/tuple/tuple.hpp>
#include <boost/tuple/tuple_comparison.hpp>
#include <map>
#include <string>
using std::string;
typedef boost::tuple<string, string, string> tpl_t;
int main() {
using boost::assign::map_list_of;
std::map<tpl_t, string> const m =
map_list_of(tpl_t("a","b","c"), "c")(tpl_t("x","y","c"), "z");
}
我会尝试
const map<x3_string_tuple, string> query_selector_map = map_list_of<x3_string_tuple, string>
(x3_string_tuple("4556", "SELECT", "FILENAME"), "4556_SELECT_FILENAME");
但是,老实说,也许只有3个单独的字符串列表更容易,然后逐个将它们组合成一个元组并将其添加到地图中。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.