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const std :: map <boost::tuples::tuple, std::string> ?

[英]const std::map<boost::tuples::tuple, std::string>?

// BOOST Includes
#include <boost/assign.hpp>             // Boost::Assign
#include <boost/assign/list_of.hpp>     // Boost::Assign::List_Of
#include <boost/assign/std/map.hpp>     // Boost::Assign::Map_List_Of
#include <boost/tuple/tuple.hpp>        // Boost::Tuples
// STD Includes
#include <map>
#include <vector>
#include <string>
// Using namespaces
using namespace std;
using namespace boost;
using namespace boost::assign;
// Consts
    const map<string, string> query_map = map_list_of<string, string>
    ("4556_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 4556")
    ("7552_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 7552")
    ("234x_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 2344 OR PMU_ID = 2345 OR PMU_ID = 2346 OR PMU_ID = 2347 OR PMU_ID = 2348")
    ("813x_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 8132 OR PMU_ID = 8133 OR PMU_ID = 8134 OR PMU_ID = 8135 OR PMU_ID = 8136");
    const map<string, std::vector<int>> vector_map = map_list_of<string, std::vector<int>>
    ("4556", list_of(4556))
    ("7552", list_of(7552))
    ("234x", list_of(2344)(2345)(2346)(2347)(2348))
    ("813x", list_of(8132)(8133)(8134)(8135)(8136));

使用boost - 可以初始化const std :: containers進行測試等。使用const std :: map或std :: map非常簡單,如上面的代碼所示。 創建一個const map<string, std::vector<int>>有點復雜 - 但仍然相當容易。

我想提出一個const std::map<boost::tuples::tuple<string, string, string>, string>但是我沒有初始化它。 還有其他人有運氣嗎?

// Typedefs
typedef boost::tuples::tuple<string, string, string> x3_string_tuple;
// Constants
const map<x3_string_tuple, string> query_selector_map = map_list_of<x3_string_tuple, string>
("4556", "SELECT", "FILENAME"), "4556_SELECT_FILENAME"); // ETC.

我嘗試了這個,它失敗了,因為地圖的鍵需要具有可比性(使用std::less ,因此需要有一個operator< defined)。 boost::tuple的比較運算符在頭文件boost/tuple/tuple_comparison.hpp中定義。

包含它,這段代碼工作正常:

#include <boost/assign/list_of.hpp>
#include <boost/tuple/tuple.hpp>
#include <boost/tuple/tuple_comparison.hpp>
#include <map>
#include <string>

using std::string;
typedef boost::tuple<string, string, string> tpl_t;

int main() {
    using boost::assign::map_list_of;
    std::map<tpl_t, string> const m = 
        map_list_of(tpl_t("a","b","c"), "c")(tpl_t("x","y","c"), "z");
}

我會嘗試

const map<x3_string_tuple, string> query_selector_map = map_list_of<x3_string_tuple, string>
(x3_string_tuple("4556", "SELECT", "FILENAME"), "4556_SELECT_FILENAME");

但是,老實說,也許只有3個單獨的字符串列表更容易,然后逐個將它們組合成一個元組並將其添加到地圖中。

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