[英]how to get rid of timestamp and change column into date format R
我有一个日期格式如下的数据集。 我想要:
1.从日期列中删除时间,使其变为2/06/2020
或更好2Jun2020
2.然后我想将我的列Date
变成日期格式,这样我就可以对其进行子集化
> print(df$Date)
[1] "2/06/2020 0:00" "12/06/2020 0:00" "12/06/2020 0:00" "29/06/2020 0:00" "3/06/2020 0:00" "25/06/2020 0:00" "25/06/2020 0:00"
[8] "25/06/2020 0:00" "26/06/2020 0:00" "18/06/2020 0:00" "3/06/2020 0:00" "4/06/2020 0:00" "10/06/2020 0:00" "10/06/2020 0:00"
> summary(df$Date)
Length Class Mode
16749 character character
我试过了,但它返回了所有NA's
:
df$Date2 <- as.Date(df$Date, format = "%d-%m-%Y %H:%M")
这是否有效:
d <- c("2/06/2020 0:00", "12/06/2020 0:00", "12/06/2020 0:00", "29/06/2020 0:00")
as.Date(gsub('(.*)(\\s\\d:\\d{2})','\\1',d),format = '%d/%m/%Y')
[1] "2020-06-02" "2020-06-12" "2020-06-12" "2020-06-29"
如果您想要02/06/2020
格式:
format(as.Date(gsub('(.*)(\\s\\d:\\d{2})','\\1',d),format = '%d/%m/%Y'),'%d/%m/%Y')
[1] "02/06/2020" "12/06/2020" "12/06/2020" "29/06/2020"
基于先前的答案:
d = "2/06/2020 0:00"
x = format(as.Date(gsub('(\\s\\0(\\d):\\0(\\d){2})','\\1',d),format = '%d/%m/%Y'),'%d/%m/%Y')
gsub("^0+(\\d)", "\\1", x)
# [1] "2/06/2020"
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