[英]How to get a value from JSON
这是我第一次使用 JSON,我试图从下面的 JSON 中提取url
。
{
"name": "The_New11d112a_Company_Name",
"sections": [
{
"name": "Products",
"payload": [
{
"id": 1,
"name": "TERi Geriatric Patient Skills Trainer,
"type": "string"
}
]
},
{
"name": "Contact Info",
"payload": [
{
"id": 1,
"name": "contacts",
"url": "https://www.a3bs.com/catheterization-kits-8000892-3011958-3b-scientific,p_1057_31043.html",
"contacts": [
{
"name": "User",
"email": "Company Email",
"phone": "Company PhoneNumber"
}
],
"type": "contact"
}
]
}
],
"tags": [
"Male",
"Airway"
],
"_id": "0e4cd5c6-4d2f-48b9-acf2-5aa75ade36e1"
}
我已经能够通过访问description
和_id
data = json.loads(line)
if 'xpath' in data:
xpath = data["_id"]
description = data["sections"][0]["payload"][0]["description"]
但是,我似乎无法找到访问url
。 另外一个问题,我已经是有可能在其他项目sections
,这使得置入到Contact Info
非首发。
希望这可以帮助:
import json
with open("test.json", "r") as f:
json_out = json.load(f)
for i in json_out["sections"]:
for j in i["payload"]:
for key in j:
if "url" in key:
print(key, '->', j[key])
我认为您的JSON已损坏,应该是这样。
{
"name": "The_New11d112a_Company_Name",
"sections": [
{
"name": "Products",
"payload": [
{
"id": 1,
"name": "TERi Geriatric Patient Skills Trainer",
"type": "string"
}
]
},
{
"name": "Contact Info",
"payload": [
{
"id": 1,
"name": "contacts",
"url": "https://www.a3bs.com/catheterization-kits-8000892-3011958-3b-scientific,p_1057_31043.html",
"contacts": [
{
"name": "User",
"email": "Company Email",
"phone": "Company PhoneNumber"
}
],
"type": "contact"
}
]
}
],
"tags": [
"Male",
"Airway"
],
"_id": "0e4cd5c6-4d2f-48b9-acf2-5aa75ade36e1"
}
您可以在http://json.parser.online.fr/上查看。
如果你想获取 url 的值。
import json
j = json.load(open('yourJSONfile.json'))
print(j['sections'][1]['payload'][0]['url'])
我认为值得编写一个简短的函数来获取url(s)
,并决定是否使用返回列表中第一个找到的url
,或者如果您的数据中没有可用的 url,则跳过处理。
该方法应如下所示:
def extract_urls(data):
payloads = []
for section in data['sections']:
payloads += section.get('payload') or []
urls = [x['url'] for x in payloads if 'url' in x]
return urls
这应该打印出 URL
import json
# open json file to read
with open('test.json','r') as f:
# load json, parameter as json text (file contents)
data = json.loads(f.read())
# after observing format of JSON data, the location of the URL key
# is determined and the data variable is manipulated to extract the value
print(data['sections'][1]['payload'][0]['url'])
'url' 键的确切位置:
数组的第一个(位置)是键“sections”的值
在数组值里面,有一个字典,key 'payload' 包含一个数组
在数组的第 0 个(位置)是一个带有键“url”的字典
在测试我的解决方案时,我注意到提供的 json 有缺陷,在修复 json 缺陷(3)后,我最终得到了这个。
{
"name": "The_New11d112a_Company_Name",
"sections": [
{
"name": "Products",
"payload": [
{
"id": 1,
"name": "TERi Geriatric Patient Skills Trainer",
"type": "string"
}
]
},
{
"name": "Contact Info",
"payload": [
{
"id": 1,
"name": "contacts",
"url": "https://www.a3bs.com/catheterization-kits-8000892-3011958-3b-scientific,p_1057_31043.html",
"contacts": [
{
"name": "User",
"email": "Company Email",
"phone": "Company PhoneNumber"
}
],
"type": "contact"
}
]
}
],
"tags": [
"Male",
"Airway"
],
"_id": "0e4cd5c6-4d2f-48b9-acf2-5aa75ade36e1"}
在使用 Vincent55 提供的 JSON 之后。 我做了一个带有异常处理和某些假设的工作代码。
工作代码:
## Assuming that the target data is always under sections[i].payload
from json import loads
line = open("data.json").read()
data = loads(line)["sections"]
for x in data:
try:
# With assumption that there is only one payload
if x["payload"][0]["url"]:
print(x["payload"][0]["url"])
except KeyError:
pass
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.