在调试控制台中等待 python vscode

Question

我有在调试模式下运行的 python 应用程序。

我想在调试模式下检查许多异步函数。

所以如果我写

await abc()

在调试控制台中它会引发错误

Traceback (most recent call last):
  File "c:\Users\sgarg\.vscode\extensions\ms-python.python-2021.8.1102490946\pythonFiles\lib\python\debugpy\_vendored\pydevd\_pydevd_bundle\pydevd_vars.py", line 419, in evaluate_expression
    compiled = compile(_expression_to_evaluate(expression), '<string>', 'eval')
  File "<string>", line 1
    a = await abc
      ^
SyntaxError: invalid syntax

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "c:\Users\sgarg\.vscode\extensions\ms-python.python-2021.8.1102490946\pythonFiles\lib\python\debugpy\_vendored\pydevd\_pydevd_bundle\pydevd_comm.py", line 1207, in internal_evaluate_expression_json
    pydevd_vars.evaluate_expression(py_db, frame, expression, is_exec=True)
  File "c:\Users\sgarg\.vscode\extensions\ms-python.python-2021.8.1102490946\pythonFiles\lib\python\debugpy\_vendored\pydevd\_pydevd_bundle\pydevd_vars.py", line 371, in new_func
    return _run_with_unblock_threads(original_func, py_db, curr_thread, frame, expression, is_exec)
  File "c:\Users\sgarg\.vscode\extensions\ms-python.python-2021.8.1102490946\pythonFiles\lib\python\debugpy\_vendored\pydevd\_pydevd_bundle\pydevd_vars.py", line 339, in _run_with_unblock_threads
    return _run_with_interrupt_thread(original_func, py_db, curr_thread, frame, expression, is_exec)
  File "c:\Users\sgarg\.vscode\extensions\ms-python.python-2021.8.1102490946\pythonFiles\lib\python\debugpy\_vendored\pydevd\_pydevd_bundle\pydevd_vars.py", line 310, in _run_with_interrupt_thread
    return original_func(py_db, frame, expression, is_exec)
  File "c:\Users\sgarg\.vscode\extensions\ms-python.python-2021.8.1102490946\pythonFiles\lib\python\debugpy\_vendored\pydevd\_pydevd_bundle\pydevd_vars.py", line 421, in evaluate_expression
    Exec(_expression_to_evaluate(expression), updated_globals, frame.f_locals)
  File "c:\Users\sgarg\.vscode\extensions\ms-python.python-2021.8.1102490946\pythonFiles\lib\python\debugpy\_vendored\pydevd\_pydevd_bundle\pydevd_exec2.py", line 3, in Exec
    exec(exp, global_vars, local_vars)
  File "<string>", line 1
SyntaxError: 'await' outside function

我试过asyncio

asyncio.run(abc())

也像这样

asyncio.get_event_loop().run_until_complete(abc())

但它显示

Traceback (most recent call last):
  File "<string>", line 1, in <module>
  File "C:\Users\sgarg\AppData\Local\Programs\Python\Python37\lib\asyncio\base_events.py", line 555, in run_until_complete
    self.run_forever()
  File "C:\Users\sgarg\AppData\Local\Programs\Python\Python37\lib\asyncio\base_events.py", line 510, in run_forever
    raise RuntimeError('This event loop is already running')
RuntimeError: This event loop is already running

它在调试点暂停。

有没有办法解决这个问题？

Answer 1

这是对此答案的修改： https://stackoverflow.com/a/67847333/17643448

此解决方案使用nest_asyncio 。 如果有以下异步示例脚本：

import asyncio
import nest_asyncio


async def abc():
    return a_json_from_a_http_request

async def foo():
    a = abc()
    print('') # Set this as is a breakpoint

def return_awaited_value(coroutine: asyncio.coroutine) -> Any:
    loop = asyncio.get_event_loop()
    result = loop.run_until_complete(coroutine)
    return result

if __name__=="__main__":
    loop = asyncio.get_event_loop()
    nest_asyncio.apply(loop) # This part is important!
    loop.run_until_complete(foo())

然后在调试控制台中，您可以执行以下操作：

result = return_awaited_value(a)

并且 VSCode 将返回运行a的结果，就好像它已等待一样，在这种情况下，它是来自 http 请求的 json，它将作为 Python 请求返回

抱歉迟了 11 个月才回复。 我刚才遇到了完全相同的问题，并花了几个小时试图解决这个问题。 这非常令人沮丧，你现在可能已经解决了/继续前进。 但我想为将来来此线程寻求答案的用户回答这个问题。