HIVE / SPARK SQL 中的 QUALIFY 等效项

Question

我正在尝试将Teradata SQL查询转换为等效的HIVE/Spark SQL 。 是否有任何替代qualify和count

SELECT
PARENT_ID, CHILD_ID
from db.source_table
QUALIFY COUNT(CHILD_ID) OVER (PARTITION BY  PARENT_ID)=0

Answer 1

知道了 ：）

select 
PARENT_ID, 
CHILD_ID
from 
(select PARENT_ID, CHILD_ID, 
    count(CHILD_ID) over (partition by PARENT_ID order by PARENT_ID asc) as COUNT_PARENT_ID 
    from db.source_table
) where COUNT_PARENT_ID = 0