[英]Why do I not get a deadlock when trying to read from a channel that never receives data in a goroutine but do in the main func
[英]Why is data being pushed into the channel but never read from the receiver goroutine?
我正在构建一个守护进程,我有两个服务将相互发送数据。 服务 A 产生数据,服务 B a 是数据缓冲区服务或类似队列。 所以从main.go
文件中,服务 B 被实例化并启动。 Start()
方法将作为 goroutine 执行buffer()
函数,因为该函数等待数据传递到通道上,我不希望主进程停止等待buffer
完成。 然后服务 A 被实例化并启动。 然后它也向服务 B“注册”。
我为服务 A 创建了一个名为RegisterWithBufferService
的方法,该方法创建了两个新通道。 它将这些通道存储为它自己的属性,并将它们提供给服务 B。
func (s *ServiceA) RegisterWithBufferService(bufService *data.DataBuffer) error {
newIncomingChan := make(chan *data.DataFrame, 1)
newOutgoingChan := make(chan []byte, 1)
s.IncomingBuffChan = newIncomingChan
s.OutgoingDataChannels = append(s.OutgoingDataChannels, newOutgoingChan)
bufService.DataProviders[s.ServiceName()] = data.DataProviderInfo{
IncomingChan: newOutgoingChan, //our outGoing channel is their incoming
OutgoingChan: newIncomingChan, // our incoming channel is their outgoing
}
s.DataBufferService = bufService
bufService.NewProvider <- s.ServiceName() //The DataBuffer service listens for new services and creates a new goroutine for buffering
s.Logger.Info().Msg("Registeration completed.")
return nil
}
Buffer 本质上侦听来自服务 A 的传入数据,使用Decode()
对其进行Decode()
,然后将其添加到名为buf
的切片中。 如果切片的长度大于bufferPeriod
那么它会将 Outgoing 通道中切片中的第一项发送回服务 A。
func (b* DataBuffer) buffer(bufferPeriod int) {
for {
select {
case newProvider := <- b.NewProvider:
b.wg.Add(1)
/*
newProvider is a string
DataProviders is a map the value it returns is a struct containing the Incoming and
Outgoing channels for this service
*/
p := b.DataProviders[newProvider]
go func(prov string, in chan []byte, out chan *DataFrame) {
defer b.wg.Done()
var buf []*DataFrame
for {
select {
case rawData := <-in:
tmp := Decode(rawData) //custom decoding function. Returns a *DataFrame
buf = append(buf, tmp)
if len(buf) < bufferPeriod {
b.Logger.Info().Msg("Sending decoded data out.")
out <- buf[0]
buf = buf[1:] //pop
}
case <- b.Quit:
return
}
}
}(newProvider, p.IncomingChan, p.OutgoingChan)
}
case <- b.Quit:
return
}
}
现在服务 A 有一个名为record
的方法,它会定期将数据推送到它的OutgoingDataChannels
属性中的所有通道。
func (s *ServiceA) record() error {
...
if atomic.LoadInt32(&s.Listeners) != 0 {
s.Logger.Info().Msg("Sending raw data to data buffer")
for _, outChan := range s.OutgoingDataChannels {
outChan <- dataBytes // the receiver (Service B) is already listening and this doesn't hang
}
s.Logger.Info().Msg("Raw data sent and received") // The logger will output this so I know it's not hanging
}
}
问题是服务 A 似乎使用record
成功推送数据,但服务 B 从未进入case rawData := <-in:
case in the buffer
sub-goroutine。 这是因为我嵌套了 goroutines 吗? 如果不清楚,当服务 B 启动时,它调用buffer
但因为否则它会挂起,我调用了一个 goroutine 来buffer
。 因此,当服务 A 调用RegisterWithBufferService
, buffer
goroutine 创建一个 goroutine 来侦听来自服务 B 的新数据,并在缓冲区填满后将其推回服务 A。 我希望我解释清楚。
编辑 1我做了一个最小的、可重现的例子。
package main
import (
"fmt"
"sync"
"sync/atomic"
"time"
)
var (
defaultBufferingPeriod int = 3
DefaultPollingInterval int64 = 10
)
type DataObject struct{
Data string
}
type DataProvider interface {
RegisterWithBufferService(*DataBuffer) error
ServiceName() string
}
type DataProviderInfo struct{
IncomingChan chan *DataObject
OutgoingChan chan *DataObject
}
type DataBuffer struct{
Running int32 //used atomically
DataProviders map[string]DataProviderInfo
Quit chan struct{}
NewProvider chan string
wg sync.WaitGroup
}
func NewDataBuffer() *DataBuffer{
var (
wg sync.WaitGroup
)
return &DataBuffer{
DataProviders: make(map[string]DataProviderInfo),
Quit: make(chan struct{}),
NewProvider: make(chan string),
wg: wg,
}
}
func (b *DataBuffer) Start() error {
if ok := atomic.CompareAndSwapInt32(&b.Running, 0, 1); !ok {
return fmt.Errorf("Could not start Data Buffer Service.")
}
go b.buffer(defaultBufferingPeriod)
return nil
}
func (b *DataBuffer) Stop() error {
if ok := atomic.CompareAndSwapInt32(&b.Running, 1, 0); !ok {
return fmt.Errorf("Could not stop Data Buffer Service.")
}
for _, p := range b.DataProviders {
close(p.IncomingChan)
close(p.OutgoingChan)
}
close(b.Quit)
b.wg.Wait()
return nil
}
// buffer creates goroutines for each incoming, outgoing data pair and decodes the incoming bytes into outgoing DataFrames
func (b *DataBuffer) buffer(bufferPeriod int) {
for {
select {
case newProvider := <- b.NewProvider:
fmt.Println("Received new Data provider.")
if _, ok := b.DataProviders[newProvider]; ok {
b.wg.Add(1)
p := b.DataProviders[newProvider]
go func(prov string, in chan *DataObject, out chan *DataObject) {
defer b.wg.Done()
var (
buf []*DataObject
)
fmt.Printf("Waiting for data from: %s\n", prov)
for {
select {
case inData := <-in:
fmt.Printf("Received data from: %s\n", prov)
buf = append(buf, inData)
if len(buf) > bufferPeriod {
fmt.Printf("Queue is filled, sending data back to %s\n", prov)
out <- buf[0]
fmt.Println("Data Sent")
buf = buf[1:] //pop
}
case <- b.Quit:
return
}
}
}(newProvider, p.IncomingChan, p.OutgoingChan)
}
case <- b.Quit:
return
}
}
}
type ServiceA struct{
Active int32 // atomic
Stopping int32 // atomic
Recording int32 // atomic
Listeners int32 // atomic
name string
QuitChan chan struct{}
IncomingBuffChan chan *DataObject
OutgoingBuffChans []chan *DataObject
DataBufferService *DataBuffer
}
// A compile time check to ensure ServiceA fully implements the DataProvider interface
var _ DataProvider = (*ServiceA)(nil)
func NewServiceA() (*ServiceA, error) {
var newSliceOutChans []chan *DataObject
return &ServiceA{
QuitChan: make(chan struct{}),
OutgoingBuffChans: newSliceOutChans,
name: "SERVICEA",
}, nil
}
// Start starts the service. Returns an error if any issues occur
func (s *ServiceA) Start() error {
atomic.StoreInt32(&s.Active, 1)
return nil
}
// Stop stops the service. Returns an error if any issues occur
func (s *ServiceA) Stop() error {
atomic.StoreInt32(&s.Stopping, 1)
close(s.QuitChan)
return nil
}
func (s *ServiceA) StartRecording(pol_int int64) error {
if ok := atomic.CompareAndSwapInt32(&s.Recording, 0, 1); !ok {
return fmt.Errorf("Could not start recording. Data recording already started")
}
ticker := time.NewTicker(time.Duration(pol_int) * time.Second)
go func() {
for {
select {
case <-ticker.C:
fmt.Println("Time to record...")
err := s.record()
if err != nil {
return
}
case <-s.QuitChan:
ticker.Stop()
return
}
}
}()
return nil
}
func (s *ServiceA) record() error {
current_time := time.Now()
ct := fmt.Sprintf("%02d-%02d-%d", current_time.Day(), current_time.Month(), current_time.Year())
dataObject := &DataObject{
Data: ct,
}
if atomic.LoadInt32(&s.Listeners) != 0 {
fmt.Println("Sending data to Data buffer...")
for _, outChan := range s.OutgoingBuffChans {
outChan <- dataObject // the receivers should already be listening
}
fmt.Println("Data sent.")
}
return nil
}
// RegisterWithBufferService satisfies the DataProvider interface. It provides the bufService with new incoming and outgoing channels along with a polling interval
func (s ServiceA) RegisterWithBufferService(bufService *DataBuffer) error {
if _, ok := bufService.DataProviders[s.ServiceName()]; ok {
return fmt.Errorf("%v data provider already registered with Data Buffer.", s.ServiceName())
}
newIncomingChan := make(chan *DataObject, 1)
newOutgoingChan := make(chan *DataObject, 1)
s.IncomingBuffChan = newIncomingChan
s.OutgoingBuffChans = append(s.OutgoingBuffChans, newOutgoingChan)
bufService.DataProviders[s.ServiceName()] = DataProviderInfo{
IncomingChan: newOutgoingChan, //our outGoing channel is their incoming
OutgoingChan: newIncomingChan, // our incoming channel is their outgoing
}
s.DataBufferService = bufService
bufService.NewProvider <- s.ServiceName() //The DataBuffer service listens for new services and creates a new goroutine for buffering
return nil
}
// ServiceName satisfies the DataProvider interface. It returns the name of the service.
func (s ServiceA) ServiceName() string {
return s.name
}
func main() {
var BufferedServices []DataProvider
fmt.Println("Instantiating and Starting Data Buffer Service...")
bufService := NewDataBuffer()
err := bufService.Start()
if err != nil {
panic(fmt.Sprintf("%v", err))
}
defer bufService.Stop()
fmt.Println("Data Buffer Service successfully started.")
fmt.Println("Instantiating and Starting Service A...")
serviceA, err := NewServiceA()
if err != nil {
panic(fmt.Sprintf("%v", err))
}
BufferedServices = append(BufferedServices, *serviceA)
err = serviceA.Start()
if err != nil {
panic(fmt.Sprintf("%v", err))
}
defer serviceA.Stop()
fmt.Println("Service A successfully started.")
fmt.Println("Registering services with Data Buffer...")
for _, s := range BufferedServices {
_ = s.RegisterWithBufferService(bufService) // ignoring error msgs for base case
}
fmt.Println("Registration complete.")
fmt.Println("Beginning recording...")
_ = atomic.AddInt32(&serviceA.Listeners, 1)
err = serviceA.StartRecording(DefaultPollingInterval)
if err != nil {
panic(fmt.Sprintf("%v", err))
}
for {
select {
case RTD := <-serviceA.IncomingBuffChan:
fmt.Println(RTD)
case <-serviceA.QuitChan:
atomic.StoreInt32(&serviceA.Listeners, 0)
bufService.Quit<-struct{}{}
}
}
}
在 Go 上运行 1.17。 运行示例时,它应该每 10 秒打印一次:
Time to record...
Sending data to Data buffer...
Data sent.
但是数据缓冲区永远不会进入inData := <-in
case。
为了诊断这一点,我将fmt.Println("Sending data to Data buffer...")
更改为fmt.Println("Sending data to Data buffer...", s.OutgoingBuffChans)
,输出为:
Time to record...
Sending data to Data buffer... []
因此,您实际上并未将数据发送到任何通道。 这样做的原因是:
func (s ServiceA) RegisterWithBufferService(bufService *DataBuffer) error {
由于在执行s.OutgoingBuffChans = append(s.OutgoingBuffChans, newOutgoingChan)
时接收者不是指针s.OutgoingBuffChans = append(s.OutgoingBuffChans, newOutgoingChan)
您正在更改ServiceA
副本中的s.OutgoingBuffChans
,该副本在函数退出时被丢弃。 要修复此更改:
func (s ServiceA) RegisterWithBufferService(bufService *DataBuffer) error {
到
func (s *ServiceA) RegisterWithBufferService(bufService *DataBuffer) error {
和
BufferedServices = append(BufferedServices, *serviceA)
到
BufferedServices = append(BufferedServices, serviceA)
修改后的版本输出:
Time to record...
Sending data to Data buffer... [0xc0000d8060]
Data sent.
Received data from: SERVICEA
Time to record...
Sending data to Data buffer... [0xc0000d8060]
Data sent.
Received data from: SERVICEA
因此,这解决了报告的问题(如果还有其他问题,我不会感到惊讶,但希望这可以为您指明正确的方向)。 我确实注意到您最初发布的代码确实使用了指针接收器,因此可能会遇到另一个问题(但在这种情况下很难对代码片段进行评论)。
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