[英]Why do I not get a deadlock when trying to read from a channel that never receives data in a goroutine but do in the main func
[英]Why is data being pushed into the channel but never read from the receiver goroutine?
我正在構建一個守護進程,我有兩個服務將相互發送數據。 服務 A 產生數據,服務 B a 是數據緩沖區服務或類似隊列。 所以從main.go
文件中,服務 B 被實例化並啟動。 Start()
方法將作為 goroutine 執行buffer()
函數,因為該函數等待數據傳遞到通道上,我不希望主進程停止等待buffer
完成。 然后服務 A 被實例化並啟動。 然后它也向服務 B“注冊”。
我為服務 A 創建了一個名為RegisterWithBufferService
的方法,該方法創建了兩個新通道。 它將這些通道存儲為它自己的屬性,並將它們提供給服務 B。
func (s *ServiceA) RegisterWithBufferService(bufService *data.DataBuffer) error {
newIncomingChan := make(chan *data.DataFrame, 1)
newOutgoingChan := make(chan []byte, 1)
s.IncomingBuffChan = newIncomingChan
s.OutgoingDataChannels = append(s.OutgoingDataChannels, newOutgoingChan)
bufService.DataProviders[s.ServiceName()] = data.DataProviderInfo{
IncomingChan: newOutgoingChan, //our outGoing channel is their incoming
OutgoingChan: newIncomingChan, // our incoming channel is their outgoing
}
s.DataBufferService = bufService
bufService.NewProvider <- s.ServiceName() //The DataBuffer service listens for new services and creates a new goroutine for buffering
s.Logger.Info().Msg("Registeration completed.")
return nil
}
Buffer 本質上偵聽來自服務 A 的傳入數據,使用Decode()
對其進行Decode()
,然后將其添加到名為buf
的切片中。 如果切片的長度大於bufferPeriod
那么它會將 Outgoing 通道中切片中的第一項發送回服務 A。
func (b* DataBuffer) buffer(bufferPeriod int) {
for {
select {
case newProvider := <- b.NewProvider:
b.wg.Add(1)
/*
newProvider is a string
DataProviders is a map the value it returns is a struct containing the Incoming and
Outgoing channels for this service
*/
p := b.DataProviders[newProvider]
go func(prov string, in chan []byte, out chan *DataFrame) {
defer b.wg.Done()
var buf []*DataFrame
for {
select {
case rawData := <-in:
tmp := Decode(rawData) //custom decoding function. Returns a *DataFrame
buf = append(buf, tmp)
if len(buf) < bufferPeriod {
b.Logger.Info().Msg("Sending decoded data out.")
out <- buf[0]
buf = buf[1:] //pop
}
case <- b.Quit:
return
}
}
}(newProvider, p.IncomingChan, p.OutgoingChan)
}
case <- b.Quit:
return
}
}
現在服務 A 有一個名為record
的方法,它會定期將數據推送到它的OutgoingDataChannels
屬性中的所有通道。
func (s *ServiceA) record() error {
...
if atomic.LoadInt32(&s.Listeners) != 0 {
s.Logger.Info().Msg("Sending raw data to data buffer")
for _, outChan := range s.OutgoingDataChannels {
outChan <- dataBytes // the receiver (Service B) is already listening and this doesn't hang
}
s.Logger.Info().Msg("Raw data sent and received") // The logger will output this so I know it's not hanging
}
}
問題是服務 A 似乎使用record
成功推送數據,但服務 B 從未進入case rawData := <-in:
case in the buffer
sub-goroutine。 這是因為我嵌套了 goroutines 嗎? 如果不清楚,當服務 B 啟動時,它調用buffer
但因為否則它會掛起,我調用了一個 goroutine 來buffer
。 因此,當服務 A 調用RegisterWithBufferService
, buffer
goroutine 創建一個 goroutine 來偵聽來自服務 B 的新數據,並在緩沖區填滿后將其推回服務 A。 我希望我解釋清楚。
編輯 1我做了一個最小的、可重現的例子。
package main
import (
"fmt"
"sync"
"sync/atomic"
"time"
)
var (
defaultBufferingPeriod int = 3
DefaultPollingInterval int64 = 10
)
type DataObject struct{
Data string
}
type DataProvider interface {
RegisterWithBufferService(*DataBuffer) error
ServiceName() string
}
type DataProviderInfo struct{
IncomingChan chan *DataObject
OutgoingChan chan *DataObject
}
type DataBuffer struct{
Running int32 //used atomically
DataProviders map[string]DataProviderInfo
Quit chan struct{}
NewProvider chan string
wg sync.WaitGroup
}
func NewDataBuffer() *DataBuffer{
var (
wg sync.WaitGroup
)
return &DataBuffer{
DataProviders: make(map[string]DataProviderInfo),
Quit: make(chan struct{}),
NewProvider: make(chan string),
wg: wg,
}
}
func (b *DataBuffer) Start() error {
if ok := atomic.CompareAndSwapInt32(&b.Running, 0, 1); !ok {
return fmt.Errorf("Could not start Data Buffer Service.")
}
go b.buffer(defaultBufferingPeriod)
return nil
}
func (b *DataBuffer) Stop() error {
if ok := atomic.CompareAndSwapInt32(&b.Running, 1, 0); !ok {
return fmt.Errorf("Could not stop Data Buffer Service.")
}
for _, p := range b.DataProviders {
close(p.IncomingChan)
close(p.OutgoingChan)
}
close(b.Quit)
b.wg.Wait()
return nil
}
// buffer creates goroutines for each incoming, outgoing data pair and decodes the incoming bytes into outgoing DataFrames
func (b *DataBuffer) buffer(bufferPeriod int) {
for {
select {
case newProvider := <- b.NewProvider:
fmt.Println("Received new Data provider.")
if _, ok := b.DataProviders[newProvider]; ok {
b.wg.Add(1)
p := b.DataProviders[newProvider]
go func(prov string, in chan *DataObject, out chan *DataObject) {
defer b.wg.Done()
var (
buf []*DataObject
)
fmt.Printf("Waiting for data from: %s\n", prov)
for {
select {
case inData := <-in:
fmt.Printf("Received data from: %s\n", prov)
buf = append(buf, inData)
if len(buf) > bufferPeriod {
fmt.Printf("Queue is filled, sending data back to %s\n", prov)
out <- buf[0]
fmt.Println("Data Sent")
buf = buf[1:] //pop
}
case <- b.Quit:
return
}
}
}(newProvider, p.IncomingChan, p.OutgoingChan)
}
case <- b.Quit:
return
}
}
}
type ServiceA struct{
Active int32 // atomic
Stopping int32 // atomic
Recording int32 // atomic
Listeners int32 // atomic
name string
QuitChan chan struct{}
IncomingBuffChan chan *DataObject
OutgoingBuffChans []chan *DataObject
DataBufferService *DataBuffer
}
// A compile time check to ensure ServiceA fully implements the DataProvider interface
var _ DataProvider = (*ServiceA)(nil)
func NewServiceA() (*ServiceA, error) {
var newSliceOutChans []chan *DataObject
return &ServiceA{
QuitChan: make(chan struct{}),
OutgoingBuffChans: newSliceOutChans,
name: "SERVICEA",
}, nil
}
// Start starts the service. Returns an error if any issues occur
func (s *ServiceA) Start() error {
atomic.StoreInt32(&s.Active, 1)
return nil
}
// Stop stops the service. Returns an error if any issues occur
func (s *ServiceA) Stop() error {
atomic.StoreInt32(&s.Stopping, 1)
close(s.QuitChan)
return nil
}
func (s *ServiceA) StartRecording(pol_int int64) error {
if ok := atomic.CompareAndSwapInt32(&s.Recording, 0, 1); !ok {
return fmt.Errorf("Could not start recording. Data recording already started")
}
ticker := time.NewTicker(time.Duration(pol_int) * time.Second)
go func() {
for {
select {
case <-ticker.C:
fmt.Println("Time to record...")
err := s.record()
if err != nil {
return
}
case <-s.QuitChan:
ticker.Stop()
return
}
}
}()
return nil
}
func (s *ServiceA) record() error {
current_time := time.Now()
ct := fmt.Sprintf("%02d-%02d-%d", current_time.Day(), current_time.Month(), current_time.Year())
dataObject := &DataObject{
Data: ct,
}
if atomic.LoadInt32(&s.Listeners) != 0 {
fmt.Println("Sending data to Data buffer...")
for _, outChan := range s.OutgoingBuffChans {
outChan <- dataObject // the receivers should already be listening
}
fmt.Println("Data sent.")
}
return nil
}
// RegisterWithBufferService satisfies the DataProvider interface. It provides the bufService with new incoming and outgoing channels along with a polling interval
func (s ServiceA) RegisterWithBufferService(bufService *DataBuffer) error {
if _, ok := bufService.DataProviders[s.ServiceName()]; ok {
return fmt.Errorf("%v data provider already registered with Data Buffer.", s.ServiceName())
}
newIncomingChan := make(chan *DataObject, 1)
newOutgoingChan := make(chan *DataObject, 1)
s.IncomingBuffChan = newIncomingChan
s.OutgoingBuffChans = append(s.OutgoingBuffChans, newOutgoingChan)
bufService.DataProviders[s.ServiceName()] = DataProviderInfo{
IncomingChan: newOutgoingChan, //our outGoing channel is their incoming
OutgoingChan: newIncomingChan, // our incoming channel is their outgoing
}
s.DataBufferService = bufService
bufService.NewProvider <- s.ServiceName() //The DataBuffer service listens for new services and creates a new goroutine for buffering
return nil
}
// ServiceName satisfies the DataProvider interface. It returns the name of the service.
func (s ServiceA) ServiceName() string {
return s.name
}
func main() {
var BufferedServices []DataProvider
fmt.Println("Instantiating and Starting Data Buffer Service...")
bufService := NewDataBuffer()
err := bufService.Start()
if err != nil {
panic(fmt.Sprintf("%v", err))
}
defer bufService.Stop()
fmt.Println("Data Buffer Service successfully started.")
fmt.Println("Instantiating and Starting Service A...")
serviceA, err := NewServiceA()
if err != nil {
panic(fmt.Sprintf("%v", err))
}
BufferedServices = append(BufferedServices, *serviceA)
err = serviceA.Start()
if err != nil {
panic(fmt.Sprintf("%v", err))
}
defer serviceA.Stop()
fmt.Println("Service A successfully started.")
fmt.Println("Registering services with Data Buffer...")
for _, s := range BufferedServices {
_ = s.RegisterWithBufferService(bufService) // ignoring error msgs for base case
}
fmt.Println("Registration complete.")
fmt.Println("Beginning recording...")
_ = atomic.AddInt32(&serviceA.Listeners, 1)
err = serviceA.StartRecording(DefaultPollingInterval)
if err != nil {
panic(fmt.Sprintf("%v", err))
}
for {
select {
case RTD := <-serviceA.IncomingBuffChan:
fmt.Println(RTD)
case <-serviceA.QuitChan:
atomic.StoreInt32(&serviceA.Listeners, 0)
bufService.Quit<-struct{}{}
}
}
}
在 Go 上運行 1.17。 運行示例時,它應該每 10 秒打印一次:
Time to record...
Sending data to Data buffer...
Data sent.
但是數據緩沖區永遠不會進入inData := <-in
case。
為了診斷這一點,我將fmt.Println("Sending data to Data buffer...")
更改為fmt.Println("Sending data to Data buffer...", s.OutgoingBuffChans)
,輸出為:
Time to record...
Sending data to Data buffer... []
因此,您實際上並未將數據發送到任何通道。 這樣做的原因是:
func (s ServiceA) RegisterWithBufferService(bufService *DataBuffer) error {
由於在執行s.OutgoingBuffChans = append(s.OutgoingBuffChans, newOutgoingChan)
時接收者不是指針s.OutgoingBuffChans = append(s.OutgoingBuffChans, newOutgoingChan)
您正在更改ServiceA
副本中的s.OutgoingBuffChans
,該副本在函數退出時被丟棄。 要修復此更改:
func (s ServiceA) RegisterWithBufferService(bufService *DataBuffer) error {
到
func (s *ServiceA) RegisterWithBufferService(bufService *DataBuffer) error {
和
BufferedServices = append(BufferedServices, *serviceA)
到
BufferedServices = append(BufferedServices, serviceA)
修改后的版本輸出:
Time to record...
Sending data to Data buffer... [0xc0000d8060]
Data sent.
Received data from: SERVICEA
Time to record...
Sending data to Data buffer... [0xc0000d8060]
Data sent.
Received data from: SERVICEA
因此,這解決了報告的問題(如果還有其他問題,我不會感到驚訝,但希望這可以為您指明正確的方向)。 我確實注意到您最初發布的代碼確實使用了指針接收器,因此可能會遇到另一個問題(但在這種情況下很難對代碼片段進行評論)。
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