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[英]How do I fix my while-loop and if conditionals in my guessAge(age) in Python?
[英]How do I continue my try/catch in my while-loop
我正在制作这款 21 点游戏,我相信如果您玩过这款游戏,您就会知道规则。 基本上我有 5 个筹码,我让用户输入他们的赌注。 我有这个 try catch 块,应该不会让用户输入低于 0 和高于chip_amount
任何chip_amount
。 我的ValueError
异常工作正常,如果用户键入“fff”或任何不是数字的内容,while 循环将继续。 如果用户输入低于 0 和高于chip_amount
任何内容,程序将退出,这是因为 while 循环停止并且我无法在 if 测试中放置continue
,我该如何解决这个问题?
print("\n==== BLACKJACK GAME ====")
print(f'\nYou have currently have {chip_amount} chips available.')
while True:
try:
chips_input = int(input("How many chips do you want to bet? "))
if chips_input < 1:
raise Exception("Sorry, you have to enter a number bigger than 1.")
if chips_input > chip_amount:
raise Exception(f'Sorry, you have to enter a number less than {chip_amount}.')
except ValueError:
print("\nYou have to enter a number!")
continue
else:
print(f'\nYou bet {chips_input} chips out of your total of {chip_amount} chips.')
print(f'\nThe cards have been dealt. You have a {" and a ".join(player_hand)}, with a total value of {player_total}.')
print(f'The dealers visible card is a {dealer_hand[0]}, with a value of {dealer_total_sliced}.')
提高 ValueErrors 以便您的 except 块也能捕获这些:
if chips_input < 1:
raise ValueError("Sorry, you have to enter a number bigger than 1.")
if chips_input > chip_amount:
raise ValueError(f'Sorry, you have to enter a number less than {chip_amount}.')
您可以在回复有效时循环而不是无限while True
循环
chip_amount = 10
print("\n==== BLACKJACK GAME ====")
print(f'\nYou have currently have {chip_amount} chips available.')
chips_input = input("How many chips do you want to bet? ")
while not chips_input.isdigit() or not chip_amount >= int(chips_input) >= 0:
print(f"False entry, enter a number between 0 and {chip_amount}")
chips_input = input("How many chips do you want to bet? ")
print(f'\nYou bet {chips_input} chips out of your total of {chip_amount} chips.')
我猜当您说“while 循环停止”时,您的意思是程序以Exception
退出。 这是因为您只是排除ValueError
异常,但您引发了一个Exception
,因此它不会被捕获并且错误会终止程序。
无论如何使用通用Exception
是不好的做法。 您应该使用从https://docs.python.org/3/library/exceptions.html 中选择一个具体的Exception
您可能可以使用ValueError
并使用当前的except
块捕获它们
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