如何使用flask-sqlalchemy进行左外连接并解决我的问题？

Question

共有三张表：

class User(db.Model):
    id = db.Column(db.Integer, primary_key=True)
    score = db.Column(db.Integer, nullable=False, default=0)
    results = db.relationship('Result', backref='solver', lazy='dynamic')

class Riddle(db.Model):
    id = db.Column(db.Integer, primary_key=True)
    text = db.Column(db.String, unique=True, nullable=False)
    answer = db.Column(db.String, nullable=False)
    solutions = db.relationship('Result', backref='rebus', lazy='dynamic')
    points = db.Column(db.Integer, default=1)

class Result(db.Model):
    id = db.Column(db.Integer, primary_key=True) 
    user_id = db.Column(db.Integer, db.ForeignKey('user.id'))
    riddle_id = db.Column(db.Integer, db.ForeignKey('riddle.id'))
    is_completed = db.Column(db.Boolean, nullable=False, default=False)

如何加入“谜语”和“结果”表并获取第一个不在用户结果中的所有字段？

简单地说，我需要获取用户在结果表中没有其 ID 的所有带有谜语的字段。

Answer 1

找到了答案：

查询语句：

SELECT *
FROM riddle
EXCEPT
SELECT riddle.*
FROM riddle
JOIN result ON result.riddle_id = riddle.id
WHERE result.user_id = 1

PYTHON：

riddle = Riddle.query.filter(Riddle.theme == theme_id) \
            .except_(Riddle.query.join(Result, Result.riddle_id == Riddle.id) \
            .filter(Result.user_id == user.id)).all()