[英]MySQL - how to select id where min/max dates difference is more than 3 years
[英]how to select years which has more than 2 movies released in mysql
我的代码是:
SELECT count(*), title, release_year
FROM film
GROUP BY release_year
HAVING COUNT(title) > 2;`
但我收到错误: #2 of SELECT 列表不在 GROUP BY 子句中,并且包含非聚合列 'sakila.film.title
它在功能上不依赖于 GROUP BY 子句中的列; 这与 sql_mode=only_full_group_by 0.038 秒不兼容
您想按 title 和 release_year 分组:
SELECT count(*), title, release_year
FROM film
GROUP BY title, release_year
HAVING COUNT(title) > 2;
或只是 release_year:
SELECT count(*), release_year
FROM film
GROUP BY release_year
HAVING COUNT(title) > 2;
可能添加GROUP_CONCAT(title)
以在一行中获取该组的所有标题。
删除title
。 如果您对x
列使用组关键字,则在select语句中仅使用x
列名和sql 函数,如 count、min、max 等。
要显示计数大于 2 的所有图块,您可以使用 GROUP _cONCAT 并且您不会再收到错误消息
SELECT count(*), GROUP_CONCAT(title SEPARATOR ';'), release_year
FROM film
GROUP BY release_year
HAVING COUNT(title) > 2;`
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