根据另一个字典列表更改字典列表中的键值的最快方法

Question

例如：我有 2 个字典列表

dictA = [{"Cases": 1, "vertical": 5, "horizontal": 10}, {"Cases": 2, "vertical": 7, "horizontal": 3},{"Cases": 3, "vertical": 2, "horizontal": 9},{"Cases": 4, "vertical": 3, "horizontal": 6}]

dictB = [{"Cases": 1, "vertical": 7, "horizontal": 8},{"Cases": 3, "vertical": 6, "horizontal": 12}]

我需要用 dictB 中的 Cases 替换 dictA 列表中“案例”= 1和3的字典，我有：

for di in dictB:
    for d in dictA:
       if d["Cases"] == di["Cases"]:
           d["vertical"] = di["vertical"]
           d["horizontal"] = di["horizontal"]

有没有更好或更快的方法来做到这一点？

Answer 1

您可以使用临时结构，其中键是Case值是来自dictB的数据，以避免双重迭代

dictA = [{"Cases": 1, "vertical": 5, "horizontal": 10}, {"Cases": 2, "vertical": 7, "horizontal": 3},
         {"Cases": 3, "vertical": 2, "horizontal": 9}, {"Cases": 4, "vertical": 3, "horizontal": 6}]
dictB = [{"Cases": 1, "vertical": 7, "horizontal": 8}, {"Cases": 3, "vertical": 6, "horizontal": 12}]
tmp_b = {x['Cases']: x for x in dictB}
print(tmp_b)  # {1: {'Cases': 1, 'vertical': 7, 'horizontal': 8}, 3: {'Cases': 3, 'vertical': 6, 'horizontal': 12}}

for d in dictA:
    d.update(tmp_b.get(d['Cases'], {}))