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如果找不到某个 driver.find_element_by_xpath,如何让我的代码跳过一行

[英]How do I make my code skip a line if a certain driver.find_element_by_xpath isnt found

从这里开始

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import time

#drivers
driver = webdriver.Chrome()
driver.get('https://www.target.com/p/plusone-waterproof-rechargeable-dual-vibrating-massager/-/A-76150669#lnk=sametab')

所以如果没有找到船,我想让 addtoCart 工作,反之亦然,

ship = driver.find_element_by_xpath('//*[@id="viewport"]/div[4]/div/div[2]/div[3]/div[1]/div/div[3]/div[1]/div[2]/button')
ship.click()

addtoCart = driver.find_element_by_xpath('//*[@id="addToCartButtonOrTextIdFor76150669"]')
addtoCart.click()

time.sleep(2)
cart = driver.get('https://www.target.com/cart')

目前正在尝试学习自动化,想制作我自己的机器人 :) 第一次在这里发帖

以下是否满足您的需求?

from selenium.common.exceptions import NoSuchElementException

try:
    ship = driver.find_element_by_xpath('//*[@id="viewport"]/div[4]/div/div[2]/div[3]/div[1]/div/div[3]/div[1]/div[2]/button')
    ship.click()
except NoSuchElementException:
    try:
        addtoCart = driver.find_element_by_xpath('//*[@id="addToCartButtonOrTextIdFor76150669"]')
        addtoCart.click()
    except NoSuchElementException:
        print("Can't click 'Ship' or 'Add to cart'")

time.sleep(2)
cart = driver.get('https://www.target.com/cart')

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