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如何在Django的下一行打印列表数据

[英]How to print list data in next line in Django

在这里,我通过 for 循环将一些数据放入列表中,这应该打印在下一行

让我们将我的 views.py 视为

def items_log(request, pk):
    logg = []
    client = request.user.client
    items_log = JobItemsLogs.objects.filter(client=client,item_id=pk).order_by('-id')[:5]
    for x in items_log:
       log_text = 'Type of entry: {0} - date: {1}; Created by: {2}'.format(
                x.type_of_entry,x.created_at.date(),x.created_by)
       logg.append(log_text)
    ...
    ...
    ...

现在让我们通过 index.html 考虑为

<div class="span4">
            <div class="well">
                <ul class="nav nav-list">
                    <li class="nav-header" >Log entries</li>

                       {% for i in logg %}
                       {{i}}
                       {% endfor %}

                </ul>
            </div>
        </div>

这里是如何显示的

实际图像

我想如何显示是

Type of entry: Plumbing - date: 2021-11-02; Created by: A Krishna*
Type of entry: Plumbing - date: 2021-11-02; Created by: A Krishna*
Type of entry: None - date: 2021-07-28; Created by: A Krishna*
Type of entry: None - date: 2021-07-28; Created by: A Krishna* 
Type of entry: None - date: 2021-07-28; Created by: A Krishna*

这些列表数据中的每一个都应该在新行中看到

只需将{{i}}放在p标签中! :D

<p>{{i}}</p>

或者您可以添加<br>

{{i}}<br>

在行后添加一个换行符 -

log_text = 'Type of entry: {0} - date: {1}; Created by: {2}<br>'.format(
                x.type_of_entry,x.created_at.date(),x.created_by)

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