Python发生异常时如何跳过执行

Question

我正在尝试在下面的代码中进行异常处理。 如果有异常，它应该跳过 try 块中的下一个语句，并应该直接转到 except 块并继续循环。

from functools import reduce

def sumnumbers(list_elements):
    try:
        sum = reduce(lambda x, y: x + y, list_elements)
        return sum
    except Exception as e:
        print("Error in function", list_elements)

a = [[1,2],[3,"hi"],[5,6],[7,8],[9,"hello"]]
for i in a:
    try:
        s = sumnumbers(i)
        print("hello ", i)
    except Exception as e:
        print(e)
        pass

实际输出：

hello  [1, 2]
Error in function [3, 'hi']
hello  [3, 'hi']
hello  [5, 6]
hello  [7, 8]
Error in function [9, 'hello']
hello  [9, 'hello']

预期输出：

hello  [1, 2]
Error in function [3, 'hi']
hello  [5, 6]
hello  [7, 8]
Error in function [9, 'hello']

Answer 1

嗨，首先，您可以查看此处以更深入地了解异常在 python 中的工作原理。

from functools import reduce

def sumnumbers(list_elements):
    try:
        sum = reduce(lambda x, y: x + y, list_elements)
        return sum
    except Exception as e:
        raise Exception("Error in function", list_elements)

a = [[1,2],[3,"hi"],[5,6],[7,8],[9,"hello"]]
for i in a:
    try:
        s = sumnumbers(i)
        print("hello ", i)
    except Exception as e:
        print(e)
        pass