[英]How to get the greatest number in a list of numbers using multiprocessing
我有一个随机数列表,我想使用multiprocessing获得最大的数字。
这是我用来生成列表的代码:
import random
randomlist = []
for i in range(100000000):
n = random.randint(1,30000000)
randomlist.append(n)
要使用串行过程获得最大数字:
import time
greatest = 0 # global variable
def f(n):
global greatest
if n>greatest:
greatest = n
if __name__ == "__main__":
global greatest
t2 = time.time()
greatest = 0
for x in randomlist:
f(x)
print("serial process took:", time.time()-t2)
print("greatest = ", greatest)
这是我尝试使用多处理获得最大数量的尝试:
from multiprocessing import Pool
import time
greatest = 0 # the global variable
def f(n):
global greatest
if n>greatest:
greatest = n
if __name__ == "__main__":
global greatest
greatest = 0
t1 = time.time()
p = Pool() #(processes=3)
result = p.map(f,randomlist)
p.close()
p.join()
print("pool took:", time.time()-t1)
print("greatest = ", greatest)
这里的输出是0,很明显没有全局变量。 如何在不影响性能的情况下解决此问题?
正如@Barmar建议,将您randomlist
分割成块,然后处理从每个块,最后计算全球最大的局部最大local_maximum_list
:
import multiprocessing as mp
import numpy as np
CHUNKSIZE = 10000
def local_maximum(l):
m = max(l)
print(f"Local maximum: {m}")
return m
if __name__ == '__main__':
randomlist = np.random.randint(1, 30000000, 100000000)
chunks = (randomlist[i:i+CHUNKSIZE]
for i in range(0, len(randomlist), CHUNKSIZE))
with mp.Pool(mp.cpu_count()) as pool:
local_maximum_list = pool.map(local_maximum, chunks)
print(f"Global maximum: {max(local_maximum_list)}")
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