我的代码正在输出一个值元组，我希望它成对出现，我需要帮助来了解如何修改它

Question

def mapper(self, _, line):
    stop_words = set(["to", "a", "an", "the", "for", "in", "on", "of", "at", "over", "with", "after", "and", "from", "new", "us", "by", "as", "man", "up", "says", "in", "out", "is", "be", "are", "not", "pm", "am", "off", "more", "less", "no", "how"])
    (date,words) = line.strip().split(",")

    word_list = words.split()
    clean_words = [word for word in word_list if word not in stop_words]
    clean_words.sort()


    yield (date[0:4],clean_words)

这是在 MRJob 映射器中。 当前输出看起来像

"2003" ["word 1","word 2", "word 3", "word 4"]
"2004" ["word 1","word 2", "word 3", "word 4"]

我希望它是：

"2003" "Word 1"
"2003" "Word 2"
"2004" "Word 3"
"2004" "Word 4"

一旦像这样输出，我就可以发送到减速器以对年份和前 3 个词进行计数

Answer 1

使用循环分别生成每个单词。

def mapper(self, _, line):
    stop_words = set(["to", "a", "an", "the", "for", "in", "on", "of", "at", "over", "with", "after", "and", "from", "new", "us", "by", "as", "man", "up", "says", "in", "out", "is", "be", "are", "not", "pm", "am", "off", "more", "less", "no", "how"])
    (date,words) = line.strip().split(",")

    word_list = words.split()
    clean_words = [word for word in word_list if word not in stop_words]
    clean_words.sort()

    for word in clean_words:
        yield (date[0:4],word)